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		<title>A Comprehensive Guide to Vapour Pressure &#124; Understanding Key Laws and Their Applications</title>
		<link>https://engineeringness.com/a-comprehensive-guide-to-vapour-pressure-understanding-key-laws-and-their-applications/</link>
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		<dc:creator><![CDATA[Hassan Ahmed]]></dc:creator>
		<pubDate>Wed, 04 Sep 2024 00:17:43 +0000</pubDate>
				<category><![CDATA[Thermodynamics]]></category>
		<category><![CDATA[Chemistry]]></category>
		<category><![CDATA[Raoult&#039;s Law]]></category>
		<category><![CDATA[Volume]]></category>
		<category><![CDATA[Vapor Pressure of Water]]></category>
		<category><![CDATA[Fractional Distillation]]></category>
		<category><![CDATA[Boiling Point]]></category>
		<category><![CDATA[Surface area]]></category>
		<category><![CDATA[Pressure]]></category>
		<category><![CDATA[vapor pressure]]></category>
		<category><![CDATA[Antoine Equation]]></category>
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					<description><![CDATA[<p>Vapour pressure is a fundamental concept in thermodynamics and physical chemistry, describing the pressure exerted by a vapour in equilibrium with its liquid or solid phase at a given temperature. It plays a critical role in various industrial processes, including distillation, evaporation, and chemical synthesis, making it essential knowledge for engineers and scientists. This article explores the principles behind vapour pressure, including key laws such as Raoult&#8217;s Law and the Antoine Equation. What Is Vapour Pressure? Vapour pressure is the pressure exerted by the vapour of a substance in thermodynamic equilibrium with its condensed phases (solid or liquid) in a</p>
<p>The post <a href="https://engineeringness.com/a-comprehensive-guide-to-vapour-pressure-understanding-key-laws-and-their-applications/" data-wpel-link="internal">A Comprehensive Guide to Vapour Pressure | Understanding Key Laws and Their Applications</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
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<p>Vapour pressure is a fundamental concept in thermodynamics and physical chemistry, describing the pressure exerted by a vapour in equilibrium with its liquid or solid phase at a given temperature. It plays a critical role in various industrial processes, including distillation, evaporation, and chemical synthesis, making it essential knowledge for engineers and scientists. </p>



<p>This article explores the principles behind vapour pressure, including key laws such as Raoult&#8217;s Law and the Antoine Equation. </p>



<h2 class="wp-block-heading">What Is Vapour Pressure?</h2>



<p>Vapour pressure is the pressure exerted by the vapour of a substance in thermodynamic equilibrium with its condensed phases (solid or liquid) in a closed system. At a given temperature, the vapour pressure represents the tendency of molecules to escape from the liquid or solid phase into the gaseous phase. </p>



<p>As <strong>temperature increases</strong>, more molecules have the energy to escape into the vapour phase, leading to an <strong>increase in vapour pressure</strong>.</p>



<p class="has-text-align-left"><span style="font-size: inherit;">This property does not depend upon quantity. It can be calculated by using the Antoine equation which expresses vapour pressure as a function of temperature.</span></p>



<h2 class="wp-block-heading">What Is The <span style="font-size: inherit;">Antoine Equation</span>? </h2>



<p>The <strong>Antoine Equation</strong> is an empirical relationship that describes the variation of vapour pressure with temperature. It is widely used because of its simplicity and accuracy for a broad range of substances.</p>



<p class="has-text-align-center"><img decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-5af8a3c4e0f4de2c17b9efc9864fc1d4_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#76;&#111;&#103;&#40;&#80;&#41;&#32;&#61;&#32;&#65;&#32;&#45;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#66;&#125;&#123;&#67;&#43;&#84;&#125;" title="Rendered by QuickLaTeX.com" height="42" width="267" style="vertical-align: -14px;"/></p>



<p><strong>Where:</strong></p>



<p><strong>T &#8211; Temperature of the liquid or substance</strong></p>



<p><strong>P &#8211; Vapour Pressure of a liquid or substance</strong></p>



<p><strong>A, B &amp; C &#8211; are liquid or substance specific constants/ coefficients</strong></p>



<p>The equation can be rearranged to calculate temperature as follows:</p>



<p class="has-text-align-center"><img decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-9fed83f27782752f510e16e1023881e2_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#84;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#32;&#123;&#66;&#125;&#123;&#45;&#76;&#111;&#103;&#40;&#80;&#41;&#32;&#43;&#32;&#65;&#125;&#32;&#45;&#32;&#67;" title="Rendered by QuickLaTeX.com" height="45" width="272" style="vertical-align: -17px;"/></p>



<p>In <em><strong>fractional distillation,</strong></em> this property plays an important role as the design of the column depends upon vapour pressure differences.</p>



<h2 class="wp-block-heading">A Brief History of The <span style="font-size: inherit;">Antoine Equation</span></h2>



<p>The Antoine Equation was developed by French engineer and chemist Louis Charles Antoine in 1888. Antoine’s work was pivotal in providing a practical tool for engineers and scientists to calculate vapour pressures at different temperatures, especially in the design and operation of distillation columns and other separation processes.</p>



<h2 class="wp-block-heading">What Are The Units of Vapour Pressure?</h2>



<p>In general value of V<sub>p</sub> is measured in the same units of pressure. As we know that there are different units available for a measure of pressure like:</p>



<ul class="wp-block-list">
<li>kg/cm<sup>2</sup> </li>



<li>PSI </li>



<li>N/m<sup>2</sup></li>



<li>kPa</li>



<li>Bar </li>



<li>Pascal</li>
</ul>



<h2 class="wp-block-heading"><span id="Factors_affecting_vapor_pressure" class="ez-toc-section"></span>Factors That Affect Vapour Pressure</h2>



<p>Some of the key factors which affect the vapour pressure are:</p>



<ul class="wp-block-list">
<li>Temperature</li>



<li>Solute concentration and nature</li>



<li>Boiling point</li>
</ul>



<h3 class="wp-block-heading"><span id="Temperature" class="ez-toc-section"></span>How Does Temperature Affect Vapour Pressure?</h3>



<p>As you increase the temperature of the solid or liquid in a system then its V<sub>p</sub> will also increase and vice versa for when it decreases.</p>



<h3 class="wp-block-heading"><span id="Solute_concentration_and_nature" class="ez-toc-section"></span>How Does Solute Concentration And Nature Affect Vapour Pressure?</h3>



<p>If you add more non-volatile solute to dissolve into a volatile solvent then the vapour pressure of the solvent will reduce, hence, in this example the more solute you add the lower the vapour pressure of the solute gets.&nbsp;</p>



<h2 class="wp-block-heading"><span id="Factor_which_not_affect_the_Vp" class="ez-toc-section"></span>Factors That Do Not Affect Vapour Pressure</h2>



<h3 class="wp-block-heading"><span id="Volume" class="ez-toc-section"></span>Volume</h3>



<p>V<sub>p</sub> does not increase or decrease with respect to the volume of its system.</p>



<h3 class="wp-block-heading">Surface Area</h3>



<p>The surface area of the solid or liquid in contact with the gas will have no effect on the vapour pressure of the system.</p>



<h2 class="wp-block-heading"><span id="What_is_Roult%E2%80%99s_Law" class="ez-toc-section"></span>What is <strong>Raoult&#8217;s Law?&nbsp;</strong></h2>



<p>Raoult&#8217;s Law is a principle that relates the vapour pressure of an ideal solution to the vapour pressures of its individual components and their mole fractions. It states that the partial vapour pressure of each component in a solution is proportional to its mole fraction in the solution and its vapour pressure when at the same temperature. It can be represented in the formula below:</p>



<p class="has-text-align-center"><img decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-6b50b0d0662843830979ddb0e7524996_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#80;&#95;&#123;&#115;&#111;&#108;&#117;&#116;&#105;&#111;&#110;&#125;&#32;&#61;&#32;&#88;&#95;&#123;&#115;&#111;&#108;&#118;&#101;&#110;&#116;&#125;&#32;&#46;&#32;&#80;&#95;&#123;&#115;&#111;&#108;&#118;&#101;&#110;&#116;&#125;" title="Rendered by QuickLaTeX.com" height="27" width="366" style="vertical-align: -5px;"/></p>



<p><strong>Where:</strong></p>



<p><strong>P<sub>solution</sub> &#8211; Vapour Pressure of the solution</strong></p>



<p><strong>X<sub>solvent</sub> &#8211; Mole fraction of the solvent</strong></p>



<p><strong>P<sub>solvent</sub> &#8211; Vapour Pressure of the pure solvent</strong></p>



<p>Raoult&#8217;s law can be used to estimate the contribution of individual components of a liquid or solid mixture to the total pressure exerted by the system.</p>



<p>We can use Raoult&#8217;s Law to calculate the vapour pressure of a given liquid. So Raoult&#8217;s Law is very helpful in the design of distillation columns. Using Raoult&#8217;s Law we can calculate the required temperature under a given vacuum in a distillation system.</p>



<h2 class="wp-block-heading">A Brief History of Raoult&#8217;s Law</h2>



<p>Raoult&#8217;s Law was first discovered by French chemist François-Marie Raoult in 1887. Raoult&#8217;s work on the connecting properties of solutions, such as freezing point depression and boiling point elevation, led to the development of this law. Although Raoult&#8217;s Law applies strictly to ideal solutions, it laid the groundwork for understanding the behaviour of real solutions, particularly in chemical engineering and thermodynamics.</p>



<h2 class="wp-block-heading"><span id="vapour_pressure_of_water" class="ez-toc-section"></span>Vapour Pressure of Water</h2>



<p>At <strong>25 degrees Celsius</strong>, the vapour pressure of water is <strong>23.8 mmHg</strong>. At <strong>100 degrees Celsius</strong>, water reaches its boiling point, and the vapour pressure becomes equal to <strong>one atmosphere</strong> (which is equivalent to 760 mmHg).</p>
<div class="saboxplugin-wrap" itemtype="http://schema.org/Person" itemscope itemprop="author"><div class="saboxplugin-tab"><div class="saboxplugin-gravatar"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/uploads/2025/02/1649882991639.jpeg" width="100"  height="100" alt="" itemprop="image"></div><div class="saboxplugin-authorname"><a href="https://engineeringness.com/author/hassan-ahmed/" class="vcard author" rel="author" data-wpel-link="internal"><span class="fn">Hassan Ahmed</span></a></div><div class="saboxplugin-desc"><div itemprop="description"><p>Hassan graduated with a Master’s degree in Chemical Engineering from the University of Chester (UK). He currently works as a design engineering consultant for one of the largest engineering firms in the world along with being an associate member of the Institute of Chemical Engineers (IChemE).</p>
</div></div><div class="clearfix"></div><div class="saboxplugin-socials "><a title="Linkedin" target="_self" href="https://www.linkedin.com/in/hassan-ahmed-961781237/" rel="noopener nofollow external noreferrer" class="saboxplugin-icon-grey" data-wpel-link="external"><svg aria-hidden="true" class="sab-linkedin" role="img" xmlns="http://www.w3.org/2000/svg" viewBox="0 0 448 512"><path fill="currentColor" d="M100.3 480H7.4V180.9h92.9V480zM53.8 140.1C24.1 140.1 0 115.5 0 85.8 0 56.1 24.1 32 53.8 32c29.7 0 53.8 24.1 53.8 53.8 0 29.7-24.1 54.3-53.8 54.3zM448 480h-92.7V334.4c0-34.7-.7-79.2-48.3-79.2-48.3 0-55.7 37.7-55.7 76.7V480h-92.8V180.9h89.1v40.8h1.3c12.4-23.5 42.7-48.3 87.9-48.3 94 0 111.3 61.9 111.3 142.3V480z"></path></svg></span></a></div></div></div><p>The post <a href="https://engineeringness.com/a-comprehensive-guide-to-vapour-pressure-understanding-key-laws-and-their-applications/" data-wpel-link="internal">A Comprehensive Guide to Vapour Pressure | Understanding Key Laws and Their Applications</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
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		<title>Factors Affecting The Rate Of A Chemical Reaction</title>
		<link>https://engineeringness.com/factors-affecting-the-rate-of-a-chemical-reaction/</link>
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		<dc:creator><![CDATA[Dr. Adam Zaidi]]></dc:creator>
		<pubDate>Tue, 01 Sep 2020 23:48:21 +0000</pubDate>
				<category><![CDATA[Kinetics]]></category>
		<category><![CDATA[Catalyst]]></category>
		<category><![CDATA[Temperature]]></category>
		<category><![CDATA[Surface area]]></category>
		<category><![CDATA[double displacement reaction]]></category>
		<category><![CDATA[Chemical Reaction]]></category>
		<category><![CDATA[Rate]]></category>
		<category><![CDATA[Concentration]]></category>
		<category><![CDATA[Physical state]]></category>
		<guid isPermaLink="false">http://52.205.3.27/?p=83381</guid>

					<description><![CDATA[<p>Reactions occur when two reactant molecules effectively collide, each having minimum energy and correct orientation. Reactant concentration, the physical state of the reactants, and surface area, temperature, and the presence of a catalyst are the main factors that affect the reaction rate. Aluminium Chloride and Sodium Hydroxide Example The best way to show the factors affecting a chemical reaction is to use an example. The chemical reaction we will look at is the double displacement reaction between Aluminium Chloride (AlCl3) and Sodium Hydroxide (NaOH) that produces Aluminium Hydroxide (Al(OH)3) and Sodium Chloride (NaCl) (equation 1). AlCl3(aq) + 3NaOH(aq)  → Al(OH)3(s)  + 3NaCl(aq) Equation 1: Double displacement reaction</p>
<p>The post <a href="https://engineeringness.com/factors-affecting-the-rate-of-a-chemical-reaction/" data-wpel-link="internal">Factors Affecting The Rate Of A Chemical Reaction</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
]]></description>
										<content:encoded><![CDATA[<p>Reactions occur when two reactant molecules effectively collide, each having minimum energy and correct orientation. Reactant concentration, the physical state of the reactants, and surface area, temperature, and the presence of a catalyst are the main factors that affect the reaction rate.</p>
<p><strong>Aluminium Chloride and Sodium Hydroxide Example</strong></p>
<p>The best way to show the factors affecting a chemical reaction is to use an example. The chemical reaction we will look at is the double displacement reaction between Aluminium Chloride (AlCl<sub>3</sub>) and Sodium Hydroxide (NaOH) that produces Aluminium Hydroxide (Al(OH)<sub>3</sub>) and Sodium Chloride (NaCl) (equation 1).</p>
<p style="text-align: center;">AlCl3(aq) + 3NaOH(aq)  → Al(OH)3(s)  + 3NaCl(aq)</p>
<p style="text-align: center;"><strong>Equation 1: Double displacement reaction between Aluminium Chloride and Sodium Hydroxide</strong></p>
<h2><u>Factors Affecting The Rate Of A Chemical Reaction:</u></h2>
<h2><strong><u>Concentration</u></strong></h2>
<p>The concentration of reactants in a chemical reaction is related to the rate of a chemical reaction. If we increase reactant concentration, then the rate of the reaction will also increase. The rate of the reaction is dependent on the concentration of both the reactants. Because the AlCl<sub>3 </sub>solution is a strong electrolyte, it dissociates completely into two ions, Al<sup>3+</sup> and Cl<sup>&#8211;</sup>. Therefore, it means that AlCl<sub>3 </sub>and Al<sup>3+</sup> ions are present in aqueous solution. In this reaction, AlCl<sub>3 </sub>is the limiting reagent, as the rate of the reaction is dependent on it.</p>
<p>While sodium hydroxide solution is not an electrolyte, but it dissociates into Na<sup>+</sup> and OH<sup>&#8211;</sup> ions. Thus, NaOH and OH<sup>&#8211;</sup>ions are present in aqueous solution. In this reaction, NaOH is the limiting reagent, in terms of concentration. This is because the rate of the reaction is dependent on it. So, this reaction is an equilibrium reaction, as it depends on the product.</p>
<p>The pH of the reaction must be in the range required by the reaction. If it is outside this range, then the reaction will be slow. For instance, in the case of the reaction between AlCl<sub>3 </sub>and NaOH, the concentration of both the reactants are equal. However, in this case, the highest concentration of the product is achieved when the reaction is carried out at pH 3, and the highest concentration of the reactant is at pH 9. So, the reaction requires the pH to be in the range of 3-9.</p>
<h2><strong><u>Physical State</u></strong></h2>
<p>The physical state of the reactants affects the rate of a chemical reaction. For instance, in the case of the reaction between AlCl<sub>3 </sub>and NaOH, if both the reactants are in the gaseous state, then it will be difficult to achieve the equilibrium. This is because gaseous reactants move away from each other, and the distance between them has a bearing on the diffusion rate. Moreover, in the gaseous state, the molecules have high kinetic energy, which slows down the rate of reaction.</p>
<p>While if both the reactants are in the solid-state, then it is easier to reach the equilibrium, in this case. Solid reactants do not have great kinetic energy. Moreover, in the solid-state, the molecules are close to each other, so it is easier to achieve equilibrium.</p>
<p>If either of the reactants is in a liquid state, then it is easy to achieve the equilibrium in the liquid state also. But, if both the reactants are in the liquid state, then it will be easier to achieve equilibrium again, as the molecules are closer to each other. Thus, the liquid state is always favourable for a reaction, the reason being that it ensures a greater number of collisions. On the other hand, free gas is less reactive as compared to a gas dissolved in a solution.</p>
<h2><strong><u>Catalyst</u></strong></h2>
<p><strong> </strong>The presence of a catalyst has an impact on the rate of the reaction. For instance, in the case of a reaction between hydrogen and oxygen, a catalyst is not required. This is because neither reaction is extremely fast, nor reactive. However, if we want a faster and more productive reaction, we can use the catalyst in this case, as well. The catalyst&#8217;s role, in this case, is to speed up the rate of reaction. But this also depends on the type of catalyst used. For instance, different catalysts react differently under different conditions.</p>
<h2><strong><u>Temperature</u></strong></h2>
<p>The temperature of the reaction has a big impact on the rate of the chemical reaction. If we increase the temperature of the reaction, hence the temperature of both the reactants, then the reaction rate will increase. Hence, the rate of chemical reactions increases with temperature.</p>
<p>In the reaction between AlCl<sub>3 </sub>and NaOH, if the temperature of the two reactants is doubled, then the rate of reaction, hence production will also increase. For instance, if we carry out the reaction at a temperature of 98°C, then the rate of reaction will increase by a factor of four, as the rate of reaction doubles with every 10° rise in temperature.</p>
<p><iframe loading="lazy" title="What happens when Sodium Hydroxide and Aluminium Reacts..? || Exothermic Reaction ||" width="1170" height="658" src="https://www.youtube.com/embed/GtFM4wTy7no?feature=oembed" frameborder="0" allow="accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share" referrerpolicy="strict-origin-when-cross-origin" allowfullscreen></iframe></p>
<h2><strong><u>Surface Area</u></strong></h2>
<p><strong> </strong>The surface area of both the reactants has a significant impact on the rate of reaction. It is because the surface area of reactants has a direct relation with the number of collisions per unit time. Therefore, if we want to increase the rate of a chemical reaction, then we must increase the surface area of both the reactants.</p>
<p>In the case of a reaction between AlCl<sub>3 </sub>and NaOH, there is no significant change in the reaction rate, whether the number of reactants is increased or the reactants change in shape or size. However, if we increase the surface area of a reactant, then the reaction rate also increases. For instance, if AlCl<sub>3 </sub>and NaOH are powdered, then the reaction rate will decrease by a factor of two, as only a small number of ions come in contact with each other. So, we can state that the rate of reaction is dependent on the surface area of the reactants. The maximum size of reactant particles in which a chemical reaction takes place at the maximum rate is called the critical size.</p>
<p>Thus, in the case of the reaction between AlCl<sub>3 </sub>and NaOH, both these reactants are powdered, hence the change in the rate of reaction is not significant. Therefore, due to the powdered nature of the reactants, the reaction rate is dependent on the size of the reactants. As a result, the reactants keep on colliding with each other, in case of powdered reactants. Hence, the rate of the reaction is higher in this scenario.</p>
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<p>The post <a href="https://engineeringness.com/factors-affecting-the-rate-of-a-chemical-reaction/" data-wpel-link="internal">Factors Affecting The Rate Of A Chemical Reaction</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
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