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		<title>An In Depth Guide To Material Balances</title>
		<link>https://engineeringness.com/an-in-depth-guide-to-material-balances/</link>
					<comments>https://engineeringness.com/an-in-depth-guide-to-material-balances/#respond</comments>
		
		<dc:creator><![CDATA[Dr. Adam Zaidi]]></dc:creator>
		<pubDate>Wed, 07 Oct 2020 21:57:07 +0000</pubDate>
				<category><![CDATA[Materials]]></category>
		<category><![CDATA[Material Balance Example]]></category>
		<category><![CDATA[conversation of mass]]></category>
		<category><![CDATA[Steady-state]]></category>
		<category><![CDATA[Unsteady state]]></category>
		<category><![CDATA[Material Balance]]></category>
		<category><![CDATA[flow system]]></category>
		<category><![CDATA[Open system]]></category>
		<category><![CDATA[Closed system]]></category>
		<category><![CDATA[System Boundary]]></category>
		<category><![CDATA[Material Balance Equation]]></category>
		<category><![CDATA[Choosing a Basis]]></category>
		<category><![CDATA[Procedure for Solving a Material Balance]]></category>
		<guid isPermaLink="false">http://52.205.3.27/?p=83561</guid>

					<description><![CDATA[<p>What Is A Material Balance? Material balances also called mass balances, is an application of the law of conversation of mass, which states matters is neither created nor destroyed. Material balances are vital for chemical engineers as they are the basis of process design and allow the design of units themselves as they determine the quantities of raw materials required for the quantity of product required. The material balance can be seen as the accounting for materials that enter and leave a process and accounts for all materials even if they undergo chemical reactions, separation, heating, cooling, mixing, drying or</p>
<p>The post <a href="https://engineeringness.com/an-in-depth-guide-to-material-balances/" data-wpel-link="internal">An In Depth Guide To Material Balances</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
]]></description>
										<content:encoded><![CDATA[<h2><u>What Is A Material Balance?</u></h2>
<p>Material balances also called mass balances, is an application of the law of conversation of mass, which states matters is neither created nor destroyed. Material balances are vital for chemical engineers as they are the basis of process design and allow the design of units themselves as they determine the quantities of raw materials required for the quantity of product required.</p>
<p>The material balance can be seen as the accounting for materials that enter and leave a process and accounts for all materials even if they undergo chemical reactions, separation, heating, cooling, mixing, drying or any other operation (excluding nuclear reactions) that occurs in the system.</p>
<p>Material balances are a really useful tool for studying plant; operations, troubleshooting, checking actual plant performance versus the design performance (what the plant works at against what it was designed for), can extend the amount of data from plant instrumentation, checks if instruments are calibrated correctly and can help locate sources of material loss.</p>
<h2><strong><u>Key Definitions </u></strong></h2>
<p><strong> </strong>A list of definitions that must be understood when doing material balances:</p>
<ul>
<li>Steady-state – Conditions at all points within the process are constant with time.</li>
<li>Unsteady state – Conditions within the process vary with time.</li>
<li>System boundary – the imaginary box is drawn around the system that is being analysed.</li>
<li>Open system (or flow system) – Materials crosses the system boundary during the process.</li>
<li>Closed system – no materials cross the system boundary except the beginning and end of the process, and changes take place within the system and heat may be transferred.</li>
</ul>
<h2><strong><u>System Boundary</u></strong></h2>
<p>The system or region needs to be defined by an imaginary closed box which is called the system boundary, which should always be drawn to avoid making any mistakes (figure 1). A system can be one single process unit, a collection of process units or an entire process.</p>
<p style="text-align: center;"><img fetchpriority="high" decoding="async" class="aligncenter wp-image-83557 size-full" src="http://engineeringness.com/wp-content/uploads/2020/10/fig-1.png" alt="" width="451" height="151" srcset="https://engineeringness.com/wp-content/uploads/2020/10/fig-1.png 451w, https://engineeringness.com/wp-content/uploads/2020/10/fig-1-300x100.png 300w" sizes="(max-width: 451px) 100vw, 451px" /></p>
<p style="text-align: center;"><strong>Figure 1: How to define a system boundary on a system</strong></p>
<h2 style="text-align: left;"><strong><u>Material Balance Equation</u></strong></h2>
<p><strong> </strong>As stated previously the material balances obey the law of conversation of mass, thus mass in is equal to mass out. The equation that needs to be remembered by every chemical engineer at all levels is:</p>
<p style="text-align: center;">Accumulation = (Mass in – Mass out) + Generation – Consumption</p>
<ul>
<li>Accumulation &#8211; The change in quantities of materials inside the system</li>
<li>Mass in – Materials entering the system that cross the system boundary</li>
<li>Mass out &#8211; Materials leaving the system that cross the system boundary</li>
<li>Generation – Materials produced by a chemical reaction that takes place within the system</li>
<li>Consumption – Materials used by a chemical reaction that takes place within the system</li>
</ul>
<h2><u>Simplification For The Material Balance Equation</u></h2>
<p><strong> </strong>In certain cases, the material balance equation will be affected:</p>
<ul>
<li>No net accumulation – as the process is in steady-state or when you have a batch vessel which starts empty and then ends empty, so no accumulation within the process, the equation becomes:</li>
</ul>
<p style="text-align: center;">In + Generation = Out + Consumption</p>
<ul>
<li>No reaction – No materials are used up such as when blending, washing or drying. Thus, no generation of a new product of consumption of starting materials, the equation becomes:</li>
</ul>
<p style="text-align: center;">Accumulation = In – Out</p>
<ul>
<li>No net accumulation or reaction – nothing is consumed, and no new products are created, and no materials remain in the process, the equation becomes:</li>
</ul>
<p style="text-align: center;">In = Out</p>
<h2><strong><u>Choosing A Basis</u></strong></h2>
<p>A basis is a reference point that you can choose when wanting to solve a problem where the information gave is limited or purposely missed out such as an exam type question. A good choice of basis makes material balances much easier to solve, and can be a flow rate, a unit of time or an amount.</p>
<p>When choosing your basis, always state your basis clearly to remove any issues that could arise from colleagues not understanding where your values came from, and for exam markers to be able to get the marks given for choosing a basis.</p>
<p>Other things that need to be considered are; the units to be used, the most convenient basis value to be used and what the question is asking. Having this checklist will make creating a basis straightforward and minimise mistakes.</p>
<p>In a scenario where one stream has enough data, then use that stream as it has the most data and if no data then assume a basis for a stream with known components, and when mass fractions are known then choose either the total mass or the mass flow rate as the basis. Similarly, if mole fractions are given then choose the total number of moles or the molar flow rate.</p>
<p>When having to choose a basis for a continuous steady-state process a sensible choice for the basis is based on the amount of material entering or leaving the system within a period i.e. Kg/hr. For a batch or semi-batch process then base the basis on the inlet amount at the feed initially or the output at the end of the process i.e. Kg/batch.</p>
<h2><strong><u>Procedure For Solving A Material Balance</u></strong></h2>
<ul>
<li>Carefully analyse the situation now what you are being asked to find or work out.</li>
<li>Label all quantities on the block flow diagram (BFD) or process flow diagram (PFD) using the units given and doing any conversions to make sure all units are the same.</li>
<li>Choose your basis, keep this simple by using easy numbers i.e. 100 kg or 1 hour.</li>
<li>Draw your system boundary.</li>
<li>State any assumptions made.</li>
<li>Draw a calculations table to make it easier to see the values you have worked out</li>
<li>Check your solution to make sure it makes sense!</li>
</ul>
<h2><strong><u>Material Balance Example</u></strong></h2>
<p>A centrifuge is used to separate particles of a diameter of 0.5 – 50 mm from a liquid.  Yeast cells are recovered from a broth (a liquid mixture containing cells) using the centrifuge. Find out the amount of cell-free discharge if per hour if 1000 L<sup>-1</sup> is the feed stream that contains 500 mg cells L<sup>-1 </sup>with a product stream that contains 50 wt% cells. Assume a density of 1 g cm<sup> 1</sup>.</p>
<p>Try to do this question without looking at the answer, if you can do this first time without looking at the answer it will be very impressive, but if you cannot don&#8217;t worry getting used to material balance questions takes time.</p>
<p>Hint: Use the procedure to solve this question and only use the information you need to be careful of red herrings!</p>
<p style="text-align: center;"><input type='hidden' bg_collapse_expand='69afdbd04fe533088402871' value='69afdbd04fe533088402871'><input type='hidden' id='bg-show-more-text-69afdbd04fe533088402871' value='Show Answer'><input type='hidden' id='bg-show-less-text-69afdbd04fe533088402871' value='Hide Answer'><button id='bg-showmore-action-69afdbd04fe533088402871' class='bg-showmore-plg-button bg-blue-button bg-eye '   style=" color:#ffffff;">Show Answer</button><div id='bg-showmore-hidden-69afdbd04fe533088402871' >
<p>Answer &#8211; Material Balance</p>
<p>The diameter of 0.5 – 50 mm, is information that isn&#8217;t required to answer this question, this is the red herring.</p>
<p>There is no accumulation as we are given a flow term and as this is a separation there are no chemical reactions, thus no consumption or generation</p>
<ul>
<li>Material balance: Mass in = Mass out</li>
<li>Only one unit is mentioned so, it a one-unit process system.</li>
<li>There are two outlet streams as on is the product and the other one which is the cell-free discharge contains no cells.</li>
</ul>
<p><strong>Basis:</strong></p>
<p>Basis has been given as per hour, so 1 hour.</p>
<p><strong>State your assumptions:</strong></p>
<ul>
<li>As mass in = mass out then steady-state</li>
<li>Two components</li>
<li>No cells in the discharge stream</li>
<li>No chemical reactions</li>
</ul>
<p><strong>Draw the process diagram</strong>, label what you have and the system boundary:</p>
<p><img decoding="async" class="aligncenter wp-image-83558 size-full" src="http://engineeringness.com/wp-content/uploads/2020/10/fig2.png" alt="" width="451" height="209" srcset="https://engineeringness.com/wp-content/uploads/2020/10/fig2.png 451w, https://engineeringness.com/wp-content/uploads/2020/10/fig2-300x139.png 300w" sizes="(max-width: 451px) 100vw, 451px" /></p>
<p><strong>Set-up calculation table:</strong></p>
<p>For this scenario:</p>
<ul>
<li>no outlet streams in the mass in section</li>
<li>no inlet streams in the mass out section</li>
<li>no cells in the cell-free discharge stream</li>
</ul>
<table class=" aligncenter" width="657">
<tbody>
<tr>
<td width="151">
<p style="text-align: center"><strong>Basis = 1 hour</strong></p>
</td>
<td style="text-align: center" colspan="3" width="236"><strong>Mass in </strong></td>
<td style="text-align: center" colspan="3" width="270"><strong>Mass out</strong></td>
</tr>
<tr>
<td width="151"><strong> </strong></td>
<td colspan="2" width="161">
<p style="text-align: center"><strong>Components</strong></p>
</td>
<td style="text-align: center" width="76"><strong>Total</strong></td>
<td style="text-align: center" colspan="2" width="178"><strong>Components</strong></td>
<td width="91">
<p style="text-align: center"><strong>Total</strong></p>
</td>
</tr>
<tr>
<td width="151"><strong> </strong></td>
<td width="76">
<p style="text-align: center"><strong>Cells</strong></p>
</td>
<td style="text-align: center" width="85"><strong>Liquid</strong></td>
<td style="text-align: center" width="76"><strong> </strong></td>
<td style="text-align: center" width="87"><strong>Cells</strong></td>
<td style="text-align: center" width="92"><strong>Liquid</strong></td>
<td style="text-align: center" width="91"><strong> </strong></td>
</tr>
<tr>
<td style="text-align: center" width="151"><strong>Feed stream</strong></td>
<td style="text-align: center" width="76"><strong> </strong></td>
<td style="text-align: center" width="85"><strong> </strong></td>
<td style="text-align: center" width="76"><strong> </strong></td>
<td style="text-align: center" width="87"><strong>0 </strong></td>
<td style="text-align: center" width="92"><strong>0 </strong></td>
<td width="91">
<p style="text-align: center"><strong>0</strong></p>
</td>
</tr>
<tr>
<td width="151">
<p style="text-align: center"><strong>Product stream</strong></p>
</td>
<td style="text-align: center" width="76"><strong> 0</strong></td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="76"><strong>0</strong></td>
<td style="text-align: center" width="87"><strong> </strong></td>
<td style="text-align: center" width="92"><strong> </strong></td>
<td width="91">
<p style="text-align: center"><strong> </strong></p>
</td>
</tr>
<tr>
<td width="151">
<p style="text-align: center"><strong>Cell-free discharge</strong></p>
</td>
<td style="text-align: center" width="76"><strong> 0</strong></td>
<td style="text-align: center" width="85"><strong>0 </strong></td>
<td style="text-align: center" width="76"><strong>0</strong></td>
<td style="text-align: center" width="87"><strong>0</strong></td>
<td style="text-align: center" width="92"><strong> </strong></td>
<td style="text-align: center" width="91"><strong> </strong></td>
</tr>
<tr>
<td style="text-align: center" width="151"><strong>Total</strong></td>
<td style="text-align: center" width="76"><strong> </strong></td>
<td style="text-align: center" width="85"><strong> </strong></td>
<td style="text-align: center" width="76"><strong> </strong></td>
<td style="text-align: center" width="87"><strong> </strong></td>
<td style="text-align: center" width="92"><strong> </strong></td>
<td width="91">
<p style="text-align: center"><strong> </strong></p>
</td>
</tr>
</tbody>
</table>
<p>Put in identifiers:</p>
<ul>
<li>Cells &#8211; C</li>
<li>Liquid &#8211; L</li>
<li>Inlet &#8211; subscript in</li>
<li>Outlet &#8211; subscript, Out</li>
<li>Cell-free discharge &#8211; D</li>
</ul>
<table class=" aligncenter" width="739">
<tbody>
<tr>
<td width="170">
<p style="text-align: center"><strong>Basis = 1 hour</strong></p>
</td>
<td style="text-align: center" colspan="3" width="266"><strong>Mass in </strong></td>
<td style="text-align: center" colspan="3" width="303"><strong>Mass out</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong> </strong></td>
<td style="text-align: center" colspan="2" width="181"><strong>Components</strong></td>
<td style="text-align: center" width="85"><strong>Total</strong></td>
<td style="text-align: center" colspan="2" width="179"><strong>Components</strong></td>
<td width="125">
<p style="text-align: center"><strong>Total</strong></p>
</td>
</tr>
<tr>
<td width="170"><strong> </strong></td>
<td width="85">
<p style="text-align: center"><strong>Cells</strong></p>
</td>
<td style="text-align: center" width="96"><strong>Liquid</strong></td>
<td style="text-align: center" width="85"><strong> </strong></td>
<td style="text-align: center" width="84"><strong>Cells</strong></td>
<td width="94">
<p style="text-align: center"><strong>Liquid</strong></p>
</td>
<td width="125"><strong> </strong></td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Feed stream</strong></p>
</td>
<td style="text-align: center" width="85"><strong>C<sub>in</sub></strong></td>
<td style="text-align: center" width="96"><strong>L<sub>in</sub></strong></td>
<td style="text-align: center" width="85"><strong>C<sub>in</sub>+L<sub>in</sub></strong></td>
<td style="text-align: center" width="84"><strong>0 </strong></td>
<td style="text-align: center" width="94"><strong>0 </strong></td>
<td style="text-align: center" width="125"><strong>0</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong>Product stream</strong></td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="96"><strong>0</strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="84"><strong>C<sub>out</sub></strong></td>
<td style="text-align: center" width="94"><strong>L<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>P<sub>out</sub>  (C<sub>out</sub>+L<sub>out</sub>)</strong></p>
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Cell-free discharge</strong></p>
</td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="96"><strong>0 </strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="84"><strong>0</strong></td>
<td style="text-align: center" width="94"><strong>D<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>D<sub>out</sub></strong></p>
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Total</strong></p>
</td>
<td style="text-align: center" width="85"><strong>C<sub>in</sub></strong></td>
<td style="text-align: center" width="96"><strong>L<sub>in</sub></strong></td>
<td style="text-align: center" width="85"><strong>C<sub>in</sub>+L<sub>in</sub></strong></td>
<td style="text-align: center" width="84"><strong>C<sub>out</sub></strong></td>
<td style="text-align: center" width="94"><strong>L<sub>out</sub>+D<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>P<sub>out</sub>+D<sub>out</sub></strong></p>
</td>
</tr>
</tbody>
</table>
<ul>
<li>Find C<sub>in</sub> and the mass of the feed stream P<sub>in</sub></li>
</ul>
<p style="text-align: center">1000 L<sup>-1</sup> is the feed stream that contains 500 mg cells L<sup>-1</sup></p>
<p style="text-align: center">500 mg cellsL broth1000 L brothhour=500 000 mg cells h-1= 500 g cells h-1</p>
<p>To make it easier for later on calculations convert mg to g, ss the basis is in calculations table.</p>
<p>To convert from litre to g you need to use the density, as you cannot go from litre to grams.</p>
<p style="text-align: center">Density = 1 g cm<sup>-3 </sup></p>
<p style="text-align: center">1000 cm<sup>3</sup> = 1 litre</p>
<p style="text-align: center">1000 L brothhour1000 cm3L1 gcm3=106 g h-1</p>
<ul>
<li>Find L<sub>in</sub></li>
</ul>
<p>Simply the mass of cells subtracted from the total mass of the stream</p>
<p style="text-align: center">Lin=(Cin+Lin)-Lin=106-500=999500 g</p>
<table class=" aligncenter" width="739">
<tbody>
<tr>
<td width="170">
<p style="text-align: center"><strong>Basis = 1 hour</strong></p>
</td>
<td style="text-align: center" colspan="3" width="266"><strong>Mass in </strong></td>
<td style="text-align: center" colspan="3" width="303"><strong>Mass out</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong> </strong></td>
<td style="text-align: center" colspan="2" width="181"><strong>Components</strong></td>
<td style="text-align: center" width="85"><strong>Total</strong></td>
<td style="text-align: center" colspan="2" width="179"><strong>Components</strong></td>
<td width="125">
<p style="text-align: center"><strong>Total</strong></p>
</td>
</tr>
<tr>
<td width="170"><strong> </strong></td>
<td width="85">
<p style="text-align: center"><strong>Cells </strong></p>
</td>
<td style="text-align: center" width="96"><strong>Liquid </strong></td>
<td style="text-align: center" width="85"><strong> </strong></td>
<td style="text-align: center" width="84"><strong>Cells </strong></td>
<td style="text-align: center" width="94"><strong>Liquid </strong></td>
<td width="125">
<p style="text-align: center">
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Feed stream (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong>500 </strong></td>
<td style="text-align: center" width="96"><strong>999500 </strong></td>
<td style="text-align: center" width="85"><strong>10<sup>6</sup> </strong></td>
<td style="text-align: center" width="84"><strong> 0</strong></td>
<td style="text-align: center" width="94"><strong> 0</strong></td>
<td style="text-align: center" width="125"><strong>0</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong>Product stream (g)</strong></td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="96"><strong>0</strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="84"><strong>C<sub>out</sub></strong></td>
<td style="text-align: center" width="94"><strong>L<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>P<sub>out</sub>  (C<sub>out</sub>+L<sub>out</sub>)</strong></p>
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Cell-free discharge (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="96"><strong>0 </strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="84"><strong>0</strong></td>
<td style="text-align: center" width="94"><strong>D<sub>out</sub></strong></td>
<td style="text-align: center" width="125"><strong>D<sub>out</sub></strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong>Total (g)</strong></td>
<td style="text-align: center" width="85"><strong>500 </strong></td>
<td style="text-align: center" width="96"><strong>999500 </strong></td>
<td style="text-align: center" width="85"><strong>10<sup>6</sup> </strong></td>
<td style="text-align: center" width="84"><strong>C<sub>out</sub></strong></td>
<td style="text-align: center" width="94"><strong>L<sub>out</sub>+D<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>P<sub>out</sub>+D<sub>out</sub></strong></p>
</td>
</tr>
</tbody>
</table>
<ul>
<li>Find C<sub>out</sub></li>
</ul>
<p style="text-align: left"><span style="text-align: center">The product cell-free discharge has no cells, thus C</span><sub style="text-align: center">in</sub><span style="text-align: center"> will be the same as C</span><sub style="text-align: center">out</sub><span style="text-align: center">.</span></p>
<table class=" aligncenter" width="739">
<tbody>
<tr>
<td width="170">
<p style="text-align: center"><strong>Basis = 1 hour</strong></p>
</td>
<td style="text-align: center" colspan="3" width="266"><strong>Mass in </strong></td>
<td style="text-align: center" colspan="3" width="303"><strong>Mass out</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong> </strong></td>
<td style="text-align: center" colspan="2" width="181"><strong>Components</strong></td>
<td style="text-align: center" width="85"><strong>Total</strong></td>
<td style="text-align: center" colspan="2" width="179"><strong>Components</strong></td>
<td width="125">
<p style="text-align: center"><strong>Total</strong></p>
</td>
</tr>
<tr>
<td width="170"><strong> </strong></td>
<td width="85">
<p style="text-align: center"><strong>Cells </strong></p>
</td>
<td style="text-align: center" width="96"><strong>Liquid </strong></td>
<td style="text-align: center" width="85"><strong> </strong></td>
<td style="text-align: center" width="84"><strong>Cells </strong></td>
<td style="text-align: center" width="94"><strong>Liquid </strong></td>
<td width="125">
<p style="text-align: center">
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Feed stream (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong>500 </strong></td>
<td style="text-align: center" width="96"><strong>999500 </strong></td>
<td style="text-align: center" width="85"><strong>10<sup>6</sup> </strong></td>
<td style="text-align: center" width="84"><strong> 0</strong></td>
<td style="text-align: center" width="94"><strong> 0</strong></td>
<td style="text-align: center" width="125"><strong>0</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong>Product stream (g)</strong></td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="96"><strong> 0</strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="84"><strong>500 </strong></td>
<td style="text-align: center" width="94"><strong>L<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>P<sub>out</sub> (C<sub>out</sub>+L<sub>out</sub>)</strong></p>
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Cell-free discharge (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="96"><strong> 0</strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="84"><strong>0</strong></td>
<td style="text-align: center" width="94"><strong>D<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>D<sub>out</sub></strong></p>
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Total (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong>500 </strong></td>
<td style="text-align: center" width="96"><strong>999500 </strong></td>
<td style="text-align: center" width="85"><strong>10<sup>6</sup> </strong></td>
<td style="text-align: center" width="84"><strong>500 </strong></td>
<td style="text-align: center" width="94"><strong>L<sub>out</sub>+D<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>P<sub>out</sub>+D<sub>out</sub></strong></p>
</td>
</tr>
</tbody>
</table>
<ul>
<li>Find P<sub>out </sub>and L<sub>out</sub></li>
</ul>
<p style="text-align: left">We are told that C<sub>out </sub>is 50wt% of the product stream, thus L<sub>out</sub> will be the other 50wt% and P<sub>out </sub>will be the sum of these two components masses</p>
<table class=" aligncenter" width="739">
<tbody>
<tr>
<td width="170">
<p style="text-align: center"><strong>Basis = 1 hour</strong></p>
</td>
<td style="text-align: center" colspan="3" width="266"><strong>Mass in </strong></td>
<td style="text-align: center" colspan="3" width="303"><strong>Mass out</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong> </strong></td>
<td style="text-align: center" colspan="2" width="181"><strong>Components</strong></td>
<td style="text-align: center" width="85"><strong>Total</strong></td>
<td style="text-align: center" colspan="2" width="179"><strong>Components</strong></td>
<td width="125">
<p style="text-align: center"><strong>Total</strong></p>
</td>
</tr>
<tr>
<td width="170"><strong> </strong></td>
<td width="85">
<p style="text-align: center"><strong>Cells </strong></p>
</td>
<td style="text-align: center" width="96"><strong>Liquid </strong></td>
<td style="text-align: center" width="85"></td>
<td style="text-align: center" width="84"><strong>Cells </strong></td>
<td width="94">
<p style="text-align: center"><strong>Liquid </strong></p>
</td>
<td width="125"><strong> </strong></td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Feed stream (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong>500 </strong></td>
<td style="text-align: center" width="96"><strong>999500 </strong></td>
<td style="text-align: center" width="85"><strong>10<sup>6</sup> </strong></td>
<td style="text-align: center" width="84"><strong> </strong></td>
<td style="text-align: center" width="94"><strong> </strong></td>
<td style="text-align: center" width="125"><strong>0</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong>Product stream (g)</strong></td>
<td style="text-align: center" width="85"><strong> </strong></td>
<td style="text-align: center" width="96"><strong> </strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="84"><strong>500 </strong></td>
<td style="text-align: center" width="94"><strong>500 </strong></td>
<td width="125">
<p style="text-align: center"><strong>1000 </strong></p>
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Cell-free discharge (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong> </strong></td>
<td style="text-align: center" width="96"><strong> </strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="84"><strong>0</strong></td>
<td style="text-align: center" width="94"><strong>D<sub>out</sub></strong></td>
<td style="text-align: center" width="125"><strong>D<sub>out</sub></strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong>Total (g)</strong></td>
<td style="text-align: center" width="85"><strong>500 </strong></td>
<td style="text-align: center" width="96"><strong>999500 </strong></td>
<td style="text-align: center" width="85"><strong>10<sup>6</sup> </strong></td>
<td style="text-align: center" width="84"><strong>500 </strong></td>
<td style="text-align: center" width="94"><strong>500  +D<sub>out</sub></strong></td>
<td width="125">
<p style="text-align: center"><strong>1000  +D<sub>out</sub></strong></p>
</td>
</tr>
</tbody>
</table>
<ul>
<li>Find D<sub>out</sub></li>
</ul>
<p>As stated previously mass in = mass out from the material balance</p>
<p style="text-align: center">106=1000+DoutDout=106-1000=999000 g</p>
<table class=" aligncenter" width="739">
<tbody>
<tr>
<td width="170">
<p style="text-align: center"><strong>Basis = 1 hour</strong></p>
</td>
<td style="text-align: center" colspan="3" width="266"><strong>Mass in </strong></td>
<td style="text-align: center" colspan="3" width="303"><strong>Mass out</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong> </strong></td>
<td style="text-align: center" colspan="2" width="181"><strong>Components</strong></td>
<td style="text-align: center" width="85"><strong>Total</strong></td>
<td style="text-align: center" colspan="2" width="216"><strong>Components</strong></td>
<td width="87">
<p style="text-align: center"><strong>Total</strong></p>
</td>
</tr>
<tr>
<td width="170"><strong> </strong></td>
<td width="85">
<p style="text-align: center"><strong>Cells</strong></p>
</td>
<td style="text-align: center" width="96"><strong>Liquid</strong></td>
<td style="text-align: center" width="85"><strong> </strong></td>
<td style="text-align: center" width="56"><strong>Cells</strong></td>
<td width="161">
<p style="text-align: center"><strong>Liquid</strong></p>
</td>
<td width="87"><strong> </strong></td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Feed stream (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong>500 </strong></td>
<td style="text-align: center" width="96"><strong>999500 </strong></td>
<td style="text-align: center" width="85"><strong>10<sup>6</sup> </strong></td>
<td style="text-align: center" width="56"><strong> 0</strong></td>
<td style="text-align: center" width="161"><strong>0 </strong></td>
<td style="text-align: center" width="87"><strong>0</strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong>Product stream (g)</strong></td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="96"><strong>0 </strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="56"><strong>500 </strong></td>
<td style="text-align: center" width="161"><strong>500 </strong></td>
<td width="87">
<p style="text-align: center"><strong>1000 </strong></p>
</td>
</tr>
<tr>
<td width="170">
<p style="text-align: center"><strong>Cell-free discharge (g)</strong></p>
</td>
<td style="text-align: center" width="85"><strong> 0</strong></td>
<td style="text-align: center" width="96"><strong> 0</strong></td>
<td style="text-align: center" width="85"><strong>0</strong></td>
<td style="text-align: center" width="56"><strong>0</strong></td>
<td style="text-align: center" width="161"><strong>999000 </strong></td>
<td style="text-align: center" width="87"><strong>999000 </strong></td>
</tr>
<tr>
<td style="text-align: center" width="170"><strong>Total (g)</strong></td>
<td style="text-align: center" width="85"><strong>500 </strong></td>
<td style="text-align: center" width="96"><strong>999500 </strong></td>
<td style="text-align: center" width="85"><strong>10<sup>6</sup> </strong></td>
<td style="text-align: center" width="56"><strong>500 </strong></td>
<td style="text-align: center" width="161"><strong>500  + 999000 </strong></td>
<td width="87">
<p style="text-align: center"><strong>10<sup>6</sup> </strong></p>
</td>
</tr>
</tbody>
</table>
<p><strong>Final checks:</strong></p>
<p>Do a check on your solutions to make sure the values make sense, and the material balance satisfies a steady-state process.</p>
<p style="text-align: center">Mass in = Mass out</p>
<p style="text-align: center">106g = 106g</p>
<p>thus, the material balance is satisfied.</p>
<p style="text-align: center"></div>
<div class="saboxplugin-wrap" itemtype="http://schema.org/Person" itemscope itemprop="author"><div class="saboxplugin-tab"><div class="saboxplugin-gravatar"><img decoding="async" src="https://engineeringness.com/wp-content/uploads/2025/04/1734789673907.jpeg" width="100"  height="100" alt="" itemprop="image"></div><div class="saboxplugin-authorname"><a href="https://engineeringness.com/author/dr-adam-zaidi/" class="vcard author" rel="author" data-wpel-link="internal"><span class="fn">Dr. Adam Zaidi</span></a></div><div class="saboxplugin-desc"><div itemprop="description"><p>Dr. Adam Zaidi, PhD, is a researcher at The University of Manchester (UK). His doctoral research focuses on reducing carbon dioxide emissions in hydrogen production processes. Adam&#8217;s expertise includes process scale-up and material development.’</p>
</div></div><div class="clearfix"></div></div></div><p>The post <a href="https://engineeringness.com/an-in-depth-guide-to-material-balances/" data-wpel-link="internal">An In Depth Guide To Material Balances</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
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		<title>An In-Depth Breakdown &#124; PFR and CSTR Reactor Design</title>
		<link>https://engineeringness.com/an-in-depth-breakdown-pfr-and-cstr-reactor-design/</link>
					<comments>https://engineeringness.com/an-in-depth-breakdown-pfr-and-cstr-reactor-design/#respond</comments>
		
		<dc:creator><![CDATA[Dr. Adam Zaidi]]></dc:creator>
		<pubDate>Sat, 29 Aug 2020 01:04:36 +0000</pubDate>
				<category><![CDATA[Kinetics]]></category>
		<category><![CDATA[PFR]]></category>
		<category><![CDATA[Reactors]]></category>
		<category><![CDATA[Flow Reactor]]></category>
		<category><![CDATA[Reactor Design]]></category>
		<category><![CDATA[Batch Reactors]]></category>
		<category><![CDATA[Continuously Stirred Tank Reactors]]></category>
		<category><![CDATA[CSTR]]></category>
		<category><![CDATA[Continuously Stirred Reactor]]></category>
		<category><![CDATA[Reactor Design Equations]]></category>
		<category><![CDATA[Material Balance]]></category>
		<category><![CDATA[Stoichiometry]]></category>
		<category><![CDATA[Plug Flow Reactor]]></category>
		<guid isPermaLink="false">http://52.205.3.27/?p=82680</guid>

					<description><![CDATA[<p>Reactor Design For reactor design, Fogler’s is a really good start for understanding the basics of reactor design and then books such as by Levenspiel are really useful once the basic knowledge has been acquired, but we will be focusing on Fogler’s algorithm for understanding of problems for reactor design that will be essential for exams and coursework’s. With reactor design relatively simple theories and models help to give insight into what is going on inside the reactor and if any changes can be made to increase the performance, however, due to this simplicity making alterations to existing designs is</p>
<p>The post <a href="https://engineeringness.com/an-in-depth-breakdown-pfr-and-cstr-reactor-design/" data-wpel-link="internal">An In-Depth Breakdown | PFR and CSTR Reactor Design</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
]]></description>
										<content:encoded><![CDATA[
<h2 class="wp-block-heading"><strong><u>Reactor Design</u></strong></h2>



<p>For reactor design, Fogler’s is a really good start for understanding the basics of reactor design and then books such as by Levenspiel are really useful once the basic knowledge has been acquired, but we will be focusing on Fogler’s algorithm for understanding of problems for reactor design that will be essential for exams and coursework’s.</p>



<p>With reactor design relatively simple theories and models help to give insight into what is going on inside the reactor and if any changes can be made to increase the performance, however, due to this simplicity making alterations to existing designs is a more preferred practice.</p>



<p>The shape of reactors can vary but they will resemble a tank or a tube for the most part and are either a batch reactor or a continuous reactor. Batch reactors have constant changing compositions and are simple to operate and aren&#8217;t steady-state, whilst continuous reactors can be two kinds PFR, Plug Flow reactor or CSTR, continuously stirred tank reactors which are used a lot in the industry due to their larger flow rates handling capabilities and control over product quality.</p>



<h2 class="wp-block-heading"><strong><u>Batch Reactor</u></strong></h2>



<figure class="wp-block-gallery aligncenter has-nested-images columns-default is-cropped wp-block-gallery-1 is-layout-flex wp-block-gallery-is-layout-flex">
<figure class="wp-block-image size-large"><img loading="lazy" decoding="async" width="443" height="535" data-id="82772" src="https://engineeringness.com/wp-content/uploads/2020/07/batch-reactor.png" alt="" class="wp-image-82772" srcset="https://engineeringness.com/wp-content/uploads/2020/07/batch-reactor.png 443w, https://engineeringness.com/wp-content/uploads/2020/07/batch-reactor-248x300.png 248w" sizes="auto, (max-width: 443px) 100vw, 443px" /></figure>
</figure>



<p class="has-text-align-center"><strong>Batch reactor schematic diagram&nbsp;(The Essential Chemical Industry &#8211; online, 2013)</strong></p>



<p>A batch reactor whilst the reaction is taking place has no flow into or out of the reactor, this is because during the reaction the batch reactor is a closed system. The reaction process in Batch reactors will produce a high conversion of the reactants however the disadvantage is the long reaction time which adds to costs such as labour costs as well as issues that are encountered in the industry such as unreliable batch qualities&nbsp;(Hafeez, 2019).</p>



<h2 class="wp-block-heading"><strong><u>Plug Flow Reactor (PFR)</u></strong></h2>



<figure class="wp-block-gallery aligncenter has-nested-images columns-default is-cropped wp-block-gallery-2 is-layout-flex wp-block-gallery-is-layout-flex">
<figure class="wp-block-image size-large"><img loading="lazy" decoding="async" width="595" height="397" data-id="82773" src="https://engineeringness.com/wp-content/uploads/2020/07/PFR.png" alt="" class="wp-image-82773" srcset="https://engineeringness.com/wp-content/uploads/2020/07/PFR.png 595w, https://engineeringness.com/wp-content/uploads/2020/07/PFR-300x200.png 300w" sizes="auto, (max-width: 595px) 100vw, 595px" /></figure>
</figure>



<p class="has-text-align-center"><strong>PFR schematic diagram (Wikipedia, 2020)</strong></p>



<p>The plug flow reactor model, PFR (sometimes called continuous tubular reactor, CTR) is a cylindrical reactor with a tubular design. The type of flow going through the PFR is called plug flow, which is modelled as infinitely thin coherent plugs (see diagram above), that travels in an axial direction with each ‘plug’ being a different entity and is effectively a small batch reactor per each plug with each plug having a different composition from before or after it. the assumption that is made for a PFR is that the fluid will be <strong>perfectly mixed in the radial</strong> direction but <strong>not mixed at all in the axial direction</strong>. The residence time (total time spent in the reactor) is an impulse (a small narrow spike function), and is derived from the position of the fluid in the PFR, and is a key factor when scaling up flow reactors&nbsp;(Vapourtec, 2020).</p>



<h2 class="wp-block-heading"><strong><u>Continuously Stirred Tank Reactors (CSTR)</u></strong></h2>



<figure class="wp-block-gallery aligncenter has-nested-images columns-default is-cropped wp-block-gallery-3 is-layout-flex wp-block-gallery-is-layout-flex">
<figure class="wp-block-image size-large"><img loading="lazy" decoding="async" width="675" height="535" data-id="83026" src="https://engineeringness.com/wp-content/uploads/2020/07/CSTR.png" alt="" class="wp-image-83026" srcset="https://engineeringness.com/wp-content/uploads/2020/07/CSTR.png 675w, https://engineeringness.com/wp-content/uploads/2020/07/CSTR-300x238.png 300w" sizes="auto, (max-width: 675px) 100vw, 675px" /></figure>
</figure>



<p class="has-text-align-center"><strong>CSTR diagram (Wikipedia, 2020)</strong></p>



<p>A continuous stirred tank reactor (CSTR) is a basically batch reactor with an impeller or other mixing device to provide efficient mixing. A CSTR is often referred to an idealised agitated vessel used to model operational variables used to attain specific outputs. Using a single CSTR leads to issue of sever back mixing, extremely poor residence time control which limit the performance of the CSTR and have a negative impact on product yield, selectivity and space-yield. Thus, to combat these issues CSTRs are used in cascades of 3 or 4 to promote better residence time control and reduce back mixing (Vapourtec, 2020).</p>



<h2 class="wp-block-heading"><strong><u>Reactor Design &#8211; Equations</u></strong></h2>



<p>To be able to find out a design parameter for a reactor you require, and the first step required a mole balance (can be called Molecular mole balance) to find out from the established system boundary of the reactor on what mass; enters, leaves, stays in the reactor or is converted into a new species.</p>



<p>A material balance must be developed, which is simply:</p>



<p class="has-text-align-center">Inlet&nbsp;Flow&nbsp;+&nbsp;Generation&nbsp;=&nbsp;Outlet&nbsp;Flow&nbsp;+&nbsp;Consumption&nbsp;+&nbsp;Accumulation</p>



<p class="has-text-align-right">(1.11)</p>



<p class="has-text-align-left">If the composition is uniform (the same at all points) in the reactor then the material balance can be done for the whole reactor, if it is not uniform then it needs to be done on an infinitesimal volume which needs to be integrated, this will become more clear when looking at batch and continuous reactors. Going forward there will be a range of notations used and making yourself familiar with these expressions is extremely important.</p>



<p class="has-text-align-left">N<sub>i</sub>&nbsp;&#8211;&nbsp;Number&nbsp;of&nbsp;moles&nbsp;of&nbsp;species&nbsp;‘i’</p>



<p class="has-text-align-left">F<sub>i</sub>&nbsp;&#8211;&nbsp;Molar&nbsp;flow&nbsp;rate&nbsp;this&nbsp;is&nbsp;used&nbsp;for&nbsp;continuous&nbsp;reactors&nbsp;at&nbsp;a&nbsp;point&nbsp;in&nbsp;the&nbsp;system</p>



<p class="has-text-align-left">X<sub>i</sub>&nbsp;&#8211;&nbsp;Conversion&nbsp;of&nbsp;species&nbsp;‘i’&nbsp;during&nbsp;the&nbsp;chemical&nbsp;reaction</p>



<p class="has-text-align-left">C<sub>i</sub>&nbsp;&#8211;&nbsp;Concentration&nbsp;of&nbsp;species&nbsp;‘i’&nbsp;at&nbsp;a&nbsp;point&nbsp;during&nbsp;the&nbsp;chemical&nbsp;reaction</p>



<p class="has-text-align-left">v&nbsp;&#8211;&nbsp;Volumetric&nbsp;flow&nbsp;rate</p>



<p class="has-text-align-left">t&nbsp;&#8211;&nbsp;Time</p>



<p class="has-text-align-left">Subscript&nbsp;‘0’&nbsp;–&nbsp;donates&nbsp;initial&nbsp;value&nbsp;when&nbsp;t&nbsp;=&nbsp;0</p>



<h2 class="wp-block-heading"><strong><u>Stoichiometry </u></strong></h2>



<p>For flow reactors:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-7bf4fda7979445645f2c4d356814cbb2_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#70;&#95;&#65;&#32;&#61;&#32;&#118;&#32;&#67;&#95;&#65;" title="Rendered by QuickLaTeX.com" height="27" width="139" style="vertical-align: -5px;"/></p>



<p class="has-text-align-right">(1.12)</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-04cd7b8d94814024d603bf1721cb108d_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#70;&#95;&#65;&#32;&#61;&#32;&#70;&#95;&#65;&#95;&#48;&#32;&#40;&#49;&#32;&#45;&#32;&#88;&#95;&#65;&#41;" title="Rendered by QuickLaTeX.com" height="32" width="258" style="vertical-align: -8px;"/></p>



<p class="has-text-align-right">(1.13)</p>



<p>&nbsp;For a batch reactor:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-68da15864191993b881fe48c5767260d_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#78;&#95;&#65;&#32;&#61;&#32;&#118;&#32;&#67;&#95;&#65;" title="Rendered by QuickLaTeX.com" height="27" width="144" style="vertical-align: -5px;"/></p>



<p class="has-text-align-right">(1.14)</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-fd74e50d0562f0dfee2e9d55cb22042c_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#78;&#95;&#65;&#32;&#61;&#32;&#78;&#95;&#65;&#95;&#48;&#32;&#40;&#49;&#32;&#45;&#32;&#88;&#95;&#65;&#41;" title="Rendered by QuickLaTeX.com" height="32" width="269" style="vertical-align: -8px;"/></p>



<p class="has-text-align-right">(1.15)</p>



<h2 class="wp-block-heading"><strong><u>Conversion</u></strong></h2>



<p>Conversion refers to the number of moles of a species that has been changed or converted into a new species, for a batch reactor this will be in terms of moles and for a continuous flow reactor this will be in terms of molar flow rates, this is simply just a division of how much of species A has been used up over the original amount of species A at t = 0.</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-5b3c6a2b6467488862cc7d75ccd9ab5d_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#88;&#95;&#65;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#78;&#95;&#65;&#95;&#48;&#32;&#45;&#32;&#78;&#95;&#65;&#125;&#123;&#32;&#78;&#95;&#65;&#95;&#48;&#125;&#32;&#92;&#108;&#101;&#102;&#116;&#97;&#114;&#114;&#111;&#119;&#32;&#66;&#97;&#116;&#99;&#104;&#32;&#82;&#101;&#97;&#99;&#116;&#111;&#114;" title="Rendered by QuickLaTeX.com" height="45" width="446" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.16)</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-cf01fa4f9f2f02e37dd3e2b5658f0513_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#88;&#95;&#65;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#70;&#95;&#65;&#95;&#48;&#32;&#45;&#32;&#70;&#95;&#65;&#125;&#123;&#70;&#95;&#65;&#95;&#48;&#125;&#32;&#92;&#108;&#101;&#102;&#116;&#97;&#114;&#114;&#111;&#119;&#32;&#70;&#108;&#111;&#119;&#32;&#82;&#101;&#97;&#99;&#116;&#111;&#114;" title="Rendered by QuickLaTeX.com" height="45" width="426" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.17)</p>



<p>There is a special case when the densities are constant, or we assume constant density we then assume the volume is constant as (density = mass/volume) for the fluid element and conversion becomes:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-18f9345fc1fff3b474ff4f8d47cf325e_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#88;&#95;&#65;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#32;&#123;&#67;&#95;&#65;&#95;&#48;&#32;&#45;&#32;&#67;&#95;&#65;&#125;&#123;&#67;&#95;&#65;&#95;&#48;&#125;" title="Rendered by QuickLaTeX.com" height="45" width="194" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.18)</p>



<p class="has-text-align-left">Equation 1.18 can be further simplified due to the fact that C<sub>A</sub>/C<sub>A0</sub> = 1 so</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-2951f13b6314d36c398271a06c2c81af_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#88;&#95;&#65;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#67;&#95;&#65;&#95;&#48;&#32;&#45;&#32;&#67;&#95;&#65;&#125;&#123;&#67;&#95;&#65;&#95;&#48;&#125;&#32;&#61;&#32;&#49;&#32;&#45;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#67;&#95;&#65;&#125;&#123;&#67;&#95;&#65;&#95;&#48;&#125;" title="Rendered by QuickLaTeX.com" height="45" width="345" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.19)</p>



<p>then this expression for conversion can be written as:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-8881f68afc21cd59a45feff43d495e47_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#88;&#95;&#65;&#32;&#61;&#32;&#45;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#67;&#95;&#65;&#32;&#125;&#123;&#67;&#95;&#65;&#95;&#48;&#125;" title="Rendered by QuickLaTeX.com" height="46" width="198" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.20)</p>



<p>C<sub>AO</sub> will be constant and the X<sub>A</sub> and C<sub>A</sub> will be changing throughout the reaction. For liquids, when the density is constant volumetric flow rates are the same throughout:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-d8b00b99b77a5680bb68110e90a3c62f_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#86;&#32;&#61;&#32;&#86;&#95;&#48;" title="Rendered by QuickLaTeX.com" height="27" width="97" style="vertical-align: -5px;"/></p>



<p class="has-text-align-right">(1.21)</p>



<h2 class="wp-block-heading"><strong><u>Space-Time and Space-Velocity </u></strong></h2>



<p>For a continuous flow reactor, space-time and space-velocity are used instead of reaction time which is used in batch reactors which represent the amount of time the reaction is going on for. Space-time (τ) is the time for the time taken for the one reactor volume of feed to go through the reactor and space-velocity (s) is how many reactor volumes of feed can be treated per unit of time.</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-0bc4389fb69d78f5aec35e87af1bdf26_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#92;&#116;&#97;&#117;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#49;&#125;&#123;&#115;&#125;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#67;&#95;&#65;&#95;&#48;&#32;&#86;&#125;&#123;&#32;&#70;&#95;&#65;&#95;&#48;&#32;&#125;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#86;&#125;&#123;&#118;&#95;&#48;&#125;" title="Rendered by QuickLaTeX.com" height="45" width="266" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.22)</p>



<h2 class="wp-block-heading"><strong><u>Ideal Batch Reactor Mole Balance</u></strong></h2>



<p>Assuming the composition is the same throughout and is well-mixed (this helps in making the mass balance easier by eliminating terms), we can do a balance on the whole reactor volume, thus the mass balance becomes</p>



<p class="has-text-align-center">0&nbsp;= Consumption&nbsp;+&nbsp;Accumulation</p>



<p class="has-text-align-right">(1.23)</p>



<p>Then stating that the consumption of species let’s call it A within the given volume:</p>



<p class="has-text-align-left">Consumption&nbsp;of&nbsp;A is equal to:</p>



<p class="has-text-align-center">-rAV←consumption&nbsp;is&nbsp;the&nbsp;reaction&nbsp;rate&nbsp;multiplied&nbsp;by&nbsp;the&nbsp;volume.</p>



<p class="has-text-align-right">(1.24)</p>



<p class="has-text-align-left">Thus the Accumulation of A is equal to:</p>



<p class="has-text-align-center"> <img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-efbc77de42cd6a6b12bf682c34f44ca4_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#78;&#95;&#65;&#125;&#123;&#32;&#92;&#68;&#101;&#108;&#116;&#97;&#116;&#125;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#78;&#95;&#65;&#95;&#48;&#32;&#40;&#49;&#32;&#45;&#32;&#88;&#95;&#65;&#41;&#125;&#123;&#32;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#116;&#125;&#32;&#61;&#32;&#45;&#78;&#95;&#65;&#95;&#48;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#88;&#95;&#65;&#125;&#32;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#116;&#125;" title="Rendered by QuickLaTeX.com" height="45" width="457" style="vertical-align: -11px;"/></p>



<p class="has-text-align-right">(1.25)</p>



<p>This gives a mole balance of:</p>



<p class="has-text-align-center"> <img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-39113712b5f92213113f7416b93cd345_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#45;&#114;&#65;&#86;&#32;&#61;&#32;&#78;&#95;&#65;&#95;&#48;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#88;&#95;&#65;&#125;&#32;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#116;&#125;" title="Rendered by QuickLaTeX.com" height="42" width="251" style="vertical-align: -11px;"/></p>



<p class="has-text-align-right">(1.26)</p>



<p>The reason for the differential is because we need to find out the conversion of species A over time.</p>



<p>Integrating gives and rearranging for t:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="292" height="86" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.06.49.png" alt="" class="wp-image-87971" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.06.49.png 292w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.06.49-60x18.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.06.49-163x48.png 163w" sizes="auto, (max-width: 292px) 100vw, 292px" /></figure>
</div>


<p class="has-text-align-right">(1.27)</p>



<p>With a constant density and thus a constant volume:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="446" height="150" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05.png" alt="" class="wp-image-87972" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05.png 446w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-300x101.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-60x20.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-143x48.png 143w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-285x96.png 285w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-313x105.png 313w" sizes="auto, (max-width: 446px) 100vw, 446px" /></figure>
</div>


<p class="has-text-align-right">(1.28)</p>



<p>(to make it easier a document will have all the final forms of the equations)</p>



<h2 class="wp-block-heading"><u><strong>CSTR Mole Balance</strong></u></h2>



<p>CSTR Mass balance: Input = output + consumption</p>



<figure class="wp-block-image size-full"><img loading="lazy" decoding="async" width="836" height="354" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28.png" alt="" class="wp-image-87977" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28.png 836w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-300x127.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-768x325.png 768w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-60x25.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-113x48.png 113w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-227x96.png 227w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-313x133.png 313w" sizes="auto, (max-width: 836px) 100vw, 836px" /></figure>



<p class="has-text-align-right">(1.29)</p>



<h2 class="wp-block-heading"><strong><u>CSTR Performance Equation</u></strong></h2>



<p><strong> </strong>The performance equation relates the reaction rate, volume, feed rate, and conversion of the species and we can rearrange the CSTR mole balance to get the performance equation and be able to work out the space-time or space velocity.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="246" height="158" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55.png" alt="" class="wp-image-87978" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55.png 246w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55-60x39.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55-75x48.png 75w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55-149x96.png 149w" sizes="auto, (max-width: 246px) 100vw, 246px" /></figure>
</div>


<p class="has-text-align-right">(1.29)</p>



<p>Then we can use the space-time equation seen previously:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="578" height="262" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10.png" alt="" class="wp-image-87979" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10.png 578w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-300x136.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-60x27.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-106x48.png 106w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-212x96.png 212w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-313x142.png 313w" sizes="auto, (max-width: 578px) 100vw, 578px" /></figure>
</div>


<h2 class="wp-block-heading"><strong><u>PFR Performance Equation</u></strong></h2>



<p><strong> </strong>Assuming constant density,</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="922" height="354" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29.png" alt="" class="wp-image-87983" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29.png 922w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-300x115.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-768x295.png 768w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-60x23.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-125x48.png 125w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-250x96.png 250w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-313x120.png 313w" sizes="auto, (max-width: 922px) 100vw, 922px" /></figure>
</div>


<p>C<sub>AF </sub>– final concentration of species A</p>



<p>If the elementary reaction is given, we can easily form an expression for r<sub>A </sub>in terms of conversion and then integrate to find out the space-time.</p>



<p>To be able to solve the integral, Simpson’s rule will need to be used, and depending on your university lecturer you could be given the Simpson’s rule formula, but if not it isn’t too hard to learn and the best way to learn is to practice and try as many variations of questions at different levels of difficulty to get used to answering these equations which are usually heavily weighted in terms of marks.</p>



<p>The equation below is Simpsons 3<sup>rd</sup> rule this can usually be used most of the time unless stated otherwise.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="732" height="110" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38.png" alt="" class="wp-image-87984" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38.png 732w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-300x45.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-60x9.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-319x48.png 319w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-639x96.png 639w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-313x47.png 313w" sizes="auto, (max-width: 732px) 100vw, 732px" /></figure>
</div>


<p class="has-text-align-right">(1.35)</p>



<h2 class="wp-block-heading"><strong><u>Changing Density </u></strong></h2>



<p>When the number of moles of gas, temperature or pressure changes then the density will no longer be constant, and we can then use the ideal gas law and then using the initial conditions and the final conditions inside the <strong>batch</strong> reactor and rationing them out:</p>



<p>Ideal gas law: pV =nRT</p>



<p>p – Pressure</p>



<p>V – Volume</p>



<p>n- Moles</p>



<p>R – Universal gas constant</p>



<p>T – Temperature</p>



<p>Initial conditions of gas:</p>



<figure class="wp-block-image size-full"><img loading="lazy" decoding="async" width="308" height="206" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02.png" alt="" class="wp-image-87985" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02.png 308w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02-300x201.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02-60x40.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02-72x48.png 72w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02-144x96.png 144w" sizes="auto, (max-width: 308px) 100vw, 308px" /></figure>



<p>Final conditions of gas: pV =nRT</p>



<p>This is simply the initial number of moles plus the change in the total number of moles due to the reaction taking place.</p>



<p>Now we will introduce epsilon, &nbsp;which is the change in the number of moles of the limiting reactant after the reaction has taken place, divided by the original number of moles.</p>



<figure class="wp-block-image size-full"><img loading="lazy" decoding="async" width="880" height="100" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35.png" alt="" class="wp-image-87986" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35.png 880w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-300x34.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-768x87.png 768w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-60x7.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-422x48.png 422w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-845x96.png 845w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-313x36.png 313w" sizes="auto, (max-width: 880px) 100vw, 880px" /></figure>



<p class="has-text-align-right">(1.39)</p>



<p>Then we can say, in a situation where species A is the limiting reagent</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="216" height="62" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.48.png" alt="" class="wp-image-87987" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.48.png 216w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.48-60x17.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.48-167x48.png 167w" sizes="auto, (max-width: 216px) 100vw, 216px" /></figure>
</div>


<p class="has-text-align-right">(1.40)</p>



<p>Remember, the total number of moles includes the leftover reactants that are in excess and any inert species that are present.</p>



<p>Using the change in moles formula, equation 1.37 into the volume equation 1.37:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="330" height="168" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07.png" alt="" class="wp-image-87989" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07.png 330w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-300x153.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-60x31.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-94x48.png 94w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-189x96.png 189w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-313x159.png 313w" sizes="auto, (max-width: 330px) 100vw, 330px" /></figure>
</div>


<p>For <strong>a flow reactor, </strong>the volume is replaced with the volume flow rate:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="320" height="108" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23.png" alt="" class="wp-image-87990" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23.png 320w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-300x101.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-60x20.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-142x48.png 142w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-284x96.png 284w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-313x106.png 313w" sizes="auto, (max-width: 320px) 100vw, 320px" /></figure>
</div>


<p class="has-text-align-right">(1.41)</p>



<p>When the density is constant, we can assume that is equal to zero.</p>



<p><strong>Example – limiting reagent </strong></p>



<p><strong>&nbsp;</strong>Air is comprised of roughly 21% oxygen, and the input feed to a reactor is 100 moles and sulphur dioxide is added as well and the input mixture is 28% sulphur dioxide and the remainder is air, the desired product is sulphur trioxide, what is the limiting reagent? and why?</p>



<p class="has-text-align-center">2SO2 + O2 → 2SO3</p>


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<p style="text-align: left"><strong>Answer – limiting reagent</strong></p>
<p><strong> </strong>Air makes up = 100 – 28 = 72 moles</p>
<p>And as oxygen is 21%, the amount of oxygen is = 0.21 x 72 = 15.12 mol</p>
<p>This means that sulphur dioxide is the limiting reagent because the 28 moles of sulphur dioxide need only 15.12 moles of oxygen to react.</p>
</div>



<h2 class="wp-block-heading"><u>References</u></h2>



<p>The Essential Chemical Industry &#8211; online. (2013, March 18). <em>Chemical reactors</em>. Retrieved from The Essential Chemical Industry &#8211; online: https://www.essentialchemicalindustry.org/processes/chemical-reactors.html</p>



<p>Vapourtec. (2020). <em>Continuous Stirred Tank Reactor (CSTR)</em>. Retrieved from Vapourtec: https://www.vapourtec.com/flow-chemistry/continuous-stirred-tank-reactor-cstr/</p>



<p>Vapourtec. (2020). <em>Plug flow reactor</em>. Retrieved from Vapourtec: https://www.vapourtec.com/flow-chemistry/plug-flow-reactor/</p>



<p>Wikipedia. (2020). <em>Continuous stirred-tank reactor</em>. Retrieved from Wikipedia: https://en.wikipedia.org/wiki/Continuous_stirred-tank_reactor</p>



<p>Wikipedia. (2020). <em>Plug flow reactor model</em>. Retrieved from Wikipedia: https://en.wikipedia.org/wiki/Plug_flow_reactor_model</p>
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