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	<title>Batch Reactors Archives - Engineeringness</title>
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		<title>An In-Depth Breakdown &#124; PFR and CSTR Reactor Design</title>
		<link>https://engineeringness.com/an-in-depth-breakdown-pfr-and-cstr-reactor-design/</link>
					<comments>https://engineeringness.com/an-in-depth-breakdown-pfr-and-cstr-reactor-design/#respond</comments>
		
		<dc:creator><![CDATA[Dr. Adam Zaidi]]></dc:creator>
		<pubDate>Sat, 29 Aug 2020 01:04:36 +0000</pubDate>
				<category><![CDATA[Kinetics]]></category>
		<category><![CDATA[Reactors]]></category>
		<category><![CDATA[Flow Reactor]]></category>
		<category><![CDATA[Reactor Design]]></category>
		<category><![CDATA[Batch Reactors]]></category>
		<category><![CDATA[Continuously Stirred Tank Reactors]]></category>
		<category><![CDATA[CSTR]]></category>
		<category><![CDATA[Continuously Stirred Reactor]]></category>
		<category><![CDATA[Reactor Design Equations]]></category>
		<category><![CDATA[Material Balance]]></category>
		<category><![CDATA[Stoichiometry]]></category>
		<category><![CDATA[Plug Flow Reactor]]></category>
		<category><![CDATA[PFR]]></category>
		<guid isPermaLink="false">http://52.205.3.27/?p=82680</guid>

					<description><![CDATA[<p>Reactor Design For reactor design, Fogler’s is a really good start for understanding the basics of reactor design and then books such as by Levenspiel are really useful once the basic knowledge has been acquired, but we will be focusing on Fogler’s algorithm for understanding of problems for reactor design that will be essential for exams and coursework’s. With reactor design relatively simple theories and models help to give insight into what is going on inside the reactor and if any changes can be made to increase the performance, however, due to this simplicity making alterations to existing designs is</p>
<p>The post <a href="https://engineeringness.com/an-in-depth-breakdown-pfr-and-cstr-reactor-design/" data-wpel-link="internal">An In-Depth Breakdown | PFR and CSTR Reactor Design</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
]]></description>
										<content:encoded><![CDATA[
<h2 class="wp-block-heading"><strong><u>Reactor Design</u></strong></h2>



<p>For reactor design, Fogler’s is a really good start for understanding the basics of reactor design and then books such as by Levenspiel are really useful once the basic knowledge has been acquired, but we will be focusing on Fogler’s algorithm for understanding of problems for reactor design that will be essential for exams and coursework’s.</p>



<p>With reactor design relatively simple theories and models help to give insight into what is going on inside the reactor and if any changes can be made to increase the performance, however, due to this simplicity making alterations to existing designs is a more preferred practice.</p>



<p>The shape of reactors can vary but they will resemble a tank or a tube for the most part and are either a batch reactor or a continuous reactor. Batch reactors have constant changing compositions and are simple to operate and aren&#8217;t steady-state, whilst continuous reactors can be two kinds PFR, Plug Flow reactor or CSTR, continuously stirred tank reactors which are used a lot in the industry due to their larger flow rates handling capabilities and control over product quality.</p>



<h2 class="wp-block-heading"><strong><u>Batch Reactor</u></strong></h2>



<figure class="wp-block-gallery aligncenter has-nested-images columns-default is-cropped wp-block-gallery-1 is-layout-flex wp-block-gallery-is-layout-flex">
<figure class="wp-block-image size-large"><img fetchpriority="high" decoding="async" width="443" height="535" data-id="82772" src="https://engineeringness.com/wp-content/uploads/2020/07/batch-reactor.png" alt="" class="wp-image-82772" srcset="https://engineeringness.com/wp-content/uploads/2020/07/batch-reactor.png 443w, https://engineeringness.com/wp-content/uploads/2020/07/batch-reactor-248x300.png 248w" sizes="(max-width: 443px) 100vw, 443px" /></figure>
</figure>



<p class="has-text-align-center"><strong>Batch reactor schematic diagram&nbsp;(The Essential Chemical Industry &#8211; online, 2013)</strong></p>



<p>A batch reactor whilst the reaction is taking place has no flow into or out of the reactor, this is because during the reaction the batch reactor is a closed system. The reaction process in Batch reactors will produce a high conversion of the reactants however the disadvantage is the long reaction time which adds to costs such as labour costs as well as issues that are encountered in the industry such as unreliable batch qualities&nbsp;(Hafeez, 2019).</p>



<h2 class="wp-block-heading"><strong><u>Plug Flow Reactor (PFR)</u></strong></h2>



<figure class="wp-block-gallery aligncenter has-nested-images columns-default is-cropped wp-block-gallery-2 is-layout-flex wp-block-gallery-is-layout-flex">
<figure class="wp-block-image size-large"><img decoding="async" width="595" height="397" data-id="82773" src="https://engineeringness.com/wp-content/uploads/2020/07/PFR.png" alt="" class="wp-image-82773" srcset="https://engineeringness.com/wp-content/uploads/2020/07/PFR.png 595w, https://engineeringness.com/wp-content/uploads/2020/07/PFR-300x200.png 300w" sizes="(max-width: 595px) 100vw, 595px" /></figure>
</figure>



<p class="has-text-align-center"><strong>PFR schematic diagram (Wikipedia, 2020)</strong></p>



<p>The plug flow reactor model, PFR (sometimes called continuous tubular reactor, CTR) is a cylindrical reactor with a tubular design. The type of flow going through the PFR is called plug flow, which is modelled as infinitely thin coherent plugs (see diagram above), that travels in an axial direction with each ‘plug’ being a different entity and is effectively a small batch reactor per each plug with each plug having a different composition from before or after it. the assumption that is made for a PFR is that the fluid will be <strong>perfectly mixed in the radial</strong> direction but <strong>not mixed at all in the axial direction</strong>. The residence time (total time spent in the reactor) is an impulse (a small narrow spike function), and is derived from the position of the fluid in the PFR, and is a key factor when scaling up flow reactors&nbsp;(Vapourtec, 2020).</p>



<h2 class="wp-block-heading"><strong><u>Continuously Stirred Tank Reactors (CSTR)</u></strong></h2>



<figure class="wp-block-gallery aligncenter has-nested-images columns-default is-cropped wp-block-gallery-3 is-layout-flex wp-block-gallery-is-layout-flex">
<figure class="wp-block-image size-large"><img decoding="async" width="675" height="535" data-id="83026" src="https://engineeringness.com/wp-content/uploads/2020/07/CSTR.png" alt="" class="wp-image-83026" srcset="https://engineeringness.com/wp-content/uploads/2020/07/CSTR.png 675w, https://engineeringness.com/wp-content/uploads/2020/07/CSTR-300x238.png 300w" sizes="(max-width: 675px) 100vw, 675px" /></figure>
</figure>



<p class="has-text-align-center"><strong>CSTR diagram (Wikipedia, 2020)</strong></p>



<p>A continuous stirred tank reactor (CSTR) is a basically batch reactor with an impeller or other mixing device to provide efficient mixing. A CSTR is often referred to an idealised agitated vessel used to model operational variables used to attain specific outputs. Using a single CSTR leads to issue of sever back mixing, extremely poor residence time control which limit the performance of the CSTR and have a negative impact on product yield, selectivity and space-yield. Thus, to combat these issues CSTRs are used in cascades of 3 or 4 to promote better residence time control and reduce back mixing (Vapourtec, 2020).</p>



<h2 class="wp-block-heading"><strong><u>Reactor Design &#8211; Equations</u></strong></h2>



<p>To be able to find out a design parameter for a reactor you require, and the first step required a mole balance (can be called Molecular mole balance) to find out from the established system boundary of the reactor on what mass; enters, leaves, stays in the reactor or is converted into a new species.</p>



<p>A material balance must be developed, which is simply:</p>



<p class="has-text-align-center">Inlet&nbsp;Flow&nbsp;+&nbsp;Generation&nbsp;=&nbsp;Outlet&nbsp;Flow&nbsp;+&nbsp;Consumption&nbsp;+&nbsp;Accumulation</p>



<p class="has-text-align-right">(1.11)</p>



<p class="has-text-align-left">If the composition is uniform (the same at all points) in the reactor then the material balance can be done for the whole reactor, if it is not uniform then it needs to be done on an infinitesimal volume which needs to be integrated, this will become more clear when looking at batch and continuous reactors. Going forward there will be a range of notations used and making yourself familiar with these expressions is extremely important.</p>



<p class="has-text-align-left">N<sub>i</sub>&nbsp;&#8211;&nbsp;Number&nbsp;of&nbsp;moles&nbsp;of&nbsp;species&nbsp;‘i’</p>



<p class="has-text-align-left">F<sub>i</sub>&nbsp;&#8211;&nbsp;Molar&nbsp;flow&nbsp;rate&nbsp;this&nbsp;is&nbsp;used&nbsp;for&nbsp;continuous&nbsp;reactors&nbsp;at&nbsp;a&nbsp;point&nbsp;in&nbsp;the&nbsp;system</p>



<p class="has-text-align-left">X<sub>i</sub>&nbsp;&#8211;&nbsp;Conversion&nbsp;of&nbsp;species&nbsp;‘i’&nbsp;during&nbsp;the&nbsp;chemical&nbsp;reaction</p>



<p class="has-text-align-left">C<sub>i</sub>&nbsp;&#8211;&nbsp;Concentration&nbsp;of&nbsp;species&nbsp;‘i’&nbsp;at&nbsp;a&nbsp;point&nbsp;during&nbsp;the&nbsp;chemical&nbsp;reaction</p>



<p class="has-text-align-left">v&nbsp;&#8211;&nbsp;Volumetric&nbsp;flow&nbsp;rate</p>



<p class="has-text-align-left">t&nbsp;&#8211;&nbsp;Time</p>



<p class="has-text-align-left">Subscript&nbsp;‘0’&nbsp;–&nbsp;donates&nbsp;initial&nbsp;value&nbsp;when&nbsp;t&nbsp;=&nbsp;0</p>



<h2 class="wp-block-heading"><strong><u>Stoichiometry </u></strong></h2>



<p>For flow reactors:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-7bf4fda7979445645f2c4d356814cbb2_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#70;&#95;&#65;&#32;&#61;&#32;&#118;&#32;&#67;&#95;&#65;" title="Rendered by QuickLaTeX.com" height="27" width="139" style="vertical-align: -5px;"/></p>



<p class="has-text-align-right">(1.12)</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-04cd7b8d94814024d603bf1721cb108d_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#70;&#95;&#65;&#32;&#61;&#32;&#70;&#95;&#65;&#95;&#48;&#32;&#40;&#49;&#32;&#45;&#32;&#88;&#95;&#65;&#41;" title="Rendered by QuickLaTeX.com" height="32" width="258" style="vertical-align: -8px;"/></p>



<p class="has-text-align-right">(1.13)</p>



<p>&nbsp;For a batch reactor:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-68da15864191993b881fe48c5767260d_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#78;&#95;&#65;&#32;&#61;&#32;&#118;&#32;&#67;&#95;&#65;" title="Rendered by QuickLaTeX.com" height="27" width="144" style="vertical-align: -5px;"/></p>



<p class="has-text-align-right">(1.14)</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-fd74e50d0562f0dfee2e9d55cb22042c_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#78;&#95;&#65;&#32;&#61;&#32;&#78;&#95;&#65;&#95;&#48;&#32;&#40;&#49;&#32;&#45;&#32;&#88;&#95;&#65;&#41;" title="Rendered by QuickLaTeX.com" height="32" width="269" style="vertical-align: -8px;"/></p>



<p class="has-text-align-right">(1.15)</p>



<h2 class="wp-block-heading"><strong><u>Conversion</u></strong></h2>



<p>Conversion refers to the number of moles of a species that has been changed or converted into a new species, for a batch reactor this will be in terms of moles and for a continuous flow reactor this will be in terms of molar flow rates, this is simply just a division of how much of species A has been used up over the original amount of species A at t = 0.</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-5b3c6a2b6467488862cc7d75ccd9ab5d_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#88;&#95;&#65;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#78;&#95;&#65;&#95;&#48;&#32;&#45;&#32;&#78;&#95;&#65;&#125;&#123;&#32;&#78;&#95;&#65;&#95;&#48;&#125;&#32;&#92;&#108;&#101;&#102;&#116;&#97;&#114;&#114;&#111;&#119;&#32;&#66;&#97;&#116;&#99;&#104;&#32;&#82;&#101;&#97;&#99;&#116;&#111;&#114;" title="Rendered by QuickLaTeX.com" height="45" width="446" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.16)</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-cf01fa4f9f2f02e37dd3e2b5658f0513_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#88;&#95;&#65;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#70;&#95;&#65;&#95;&#48;&#32;&#45;&#32;&#70;&#95;&#65;&#125;&#123;&#70;&#95;&#65;&#95;&#48;&#125;&#32;&#92;&#108;&#101;&#102;&#116;&#97;&#114;&#114;&#111;&#119;&#32;&#70;&#108;&#111;&#119;&#32;&#82;&#101;&#97;&#99;&#116;&#111;&#114;" title="Rendered by QuickLaTeX.com" height="45" width="426" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.17)</p>



<p>There is a special case when the densities are constant, or we assume constant density we then assume the volume is constant as (density = mass/volume) for the fluid element and conversion becomes:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-18f9345fc1fff3b474ff4f8d47cf325e_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#88;&#95;&#65;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#32;&#123;&#67;&#95;&#65;&#95;&#48;&#32;&#45;&#32;&#67;&#95;&#65;&#125;&#123;&#67;&#95;&#65;&#95;&#48;&#125;" title="Rendered by QuickLaTeX.com" height="45" width="194" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.18)</p>



<p class="has-text-align-left">Equation 1.18 can be further simplified due to the fact that C<sub>A</sub>/C<sub>A0</sub> = 1 so</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-2951f13b6314d36c398271a06c2c81af_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#88;&#95;&#65;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#67;&#95;&#65;&#95;&#48;&#32;&#45;&#32;&#67;&#95;&#65;&#125;&#123;&#67;&#95;&#65;&#95;&#48;&#125;&#32;&#61;&#32;&#49;&#32;&#45;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#67;&#95;&#65;&#125;&#123;&#67;&#95;&#65;&#95;&#48;&#125;" title="Rendered by QuickLaTeX.com" height="45" width="345" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.19)</p>



<p>then this expression for conversion can be written as:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-8881f68afc21cd59a45feff43d495e47_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#88;&#95;&#65;&#32;&#61;&#32;&#45;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#67;&#95;&#65;&#32;&#125;&#123;&#67;&#95;&#65;&#95;&#48;&#125;" title="Rendered by QuickLaTeX.com" height="46" width="198" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.20)</p>



<p>C<sub>AO</sub> will be constant and the X<sub>A</sub> and C<sub>A</sub> will be changing throughout the reaction. For liquids, when the density is constant volumetric flow rates are the same throughout:</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-d8b00b99b77a5680bb68110e90a3c62f_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#86;&#32;&#61;&#32;&#86;&#95;&#48;" title="Rendered by QuickLaTeX.com" height="27" width="97" style="vertical-align: -5px;"/></p>



<p class="has-text-align-right">(1.21)</p>



<h2 class="wp-block-heading"><strong><u>Space-Time and Space-Velocity </u></strong></h2>



<p>For a continuous flow reactor, space-time and space-velocity are used instead of reaction time which is used in batch reactors which represent the amount of time the reaction is going on for. Space-time (τ) is the time for the time taken for the one reactor volume of feed to go through the reactor and space-velocity (s) is how many reactor volumes of feed can be treated per unit of time.</p>



<p class="has-text-align-center"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-0bc4389fb69d78f5aec35e87af1bdf26_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#92;&#116;&#97;&#117;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#49;&#125;&#123;&#115;&#125;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#67;&#95;&#65;&#95;&#48;&#32;&#86;&#125;&#123;&#32;&#70;&#95;&#65;&#95;&#48;&#32;&#125;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#86;&#125;&#123;&#118;&#95;&#48;&#125;" title="Rendered by QuickLaTeX.com" height="45" width="266" style="vertical-align: -15px;"/></p>



<p class="has-text-align-right">(1.22)</p>



<h2 class="wp-block-heading"><strong><u>Ideal Batch Reactor Mole Balance</u></strong></h2>



<p>Assuming the composition is the same throughout and is well-mixed (this helps in making the mass balance easier by eliminating terms), we can do a balance on the whole reactor volume, thus the mass balance becomes</p>



<p class="has-text-align-center">0&nbsp;= Consumption&nbsp;+&nbsp;Accumulation</p>



<p class="has-text-align-right">(1.23)</p>



<p>Then stating that the consumption of species let’s call it A within the given volume:</p>



<p class="has-text-align-left">Consumption&nbsp;of&nbsp;A is equal to:</p>



<p class="has-text-align-center">-rAV←consumption&nbsp;is&nbsp;the&nbsp;reaction&nbsp;rate&nbsp;multiplied&nbsp;by&nbsp;the&nbsp;volume.</p>



<p class="has-text-align-right">(1.24)</p>



<p class="has-text-align-left">Thus the Accumulation of A is equal to:</p>



<p class="has-text-align-center"> <img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-efbc77de42cd6a6b12bf682c34f44ca4_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#78;&#95;&#65;&#125;&#123;&#32;&#92;&#68;&#101;&#108;&#116;&#97;&#116;&#125;&#32;&#61;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#78;&#95;&#65;&#95;&#48;&#32;&#40;&#49;&#32;&#45;&#32;&#88;&#95;&#65;&#41;&#125;&#123;&#32;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#116;&#125;&#32;&#61;&#32;&#45;&#78;&#95;&#65;&#95;&#48;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#88;&#95;&#65;&#125;&#32;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#116;&#125;" title="Rendered by QuickLaTeX.com" height="45" width="457" style="vertical-align: -11px;"/></p>



<p class="has-text-align-right">(1.25)</p>



<p>This gives a mole balance of:</p>



<p class="has-text-align-center"> <img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/ql-cache/quicklatex.com-39113712b5f92213113f7416b93cd345_l3.png" class="ql-img-inline-formula quicklatex-auto-format" alt="&#45;&#114;&#65;&#86;&#32;&#61;&#32;&#78;&#95;&#65;&#95;&#48;&#32;&#92;&#102;&#114;&#97;&#99;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#88;&#95;&#65;&#125;&#32;&#123;&#92;&#68;&#101;&#108;&#116;&#97;&#32;&#116;&#125;" title="Rendered by QuickLaTeX.com" height="42" width="251" style="vertical-align: -11px;"/></p>



<p class="has-text-align-right">(1.26)</p>



<p>The reason for the differential is because we need to find out the conversion of species A over time.</p>



<p>Integrating gives and rearranging for t:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="292" height="86" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.06.49.png" alt="" class="wp-image-87971" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.06.49.png 292w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.06.49-60x18.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.06.49-163x48.png 163w" sizes="auto, (max-width: 292px) 100vw, 292px" /></figure>
</div>


<p class="has-text-align-right">(1.27)</p>



<p>With a constant density and thus a constant volume:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="446" height="150" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05.png" alt="" class="wp-image-87972" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05.png 446w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-300x101.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-60x20.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-143x48.png 143w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-285x96.png 285w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.07.05-313x105.png 313w" sizes="auto, (max-width: 446px) 100vw, 446px" /></figure>
</div>


<p class="has-text-align-right">(1.28)</p>



<p>(to make it easier a document will have all the final forms of the equations)</p>



<h2 class="wp-block-heading"><u><strong>CSTR Mole Balance</strong></u></h2>



<p>CSTR Mass balance: Input = output + consumption</p>



<figure class="wp-block-image size-full"><img loading="lazy" decoding="async" width="836" height="354" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28.png" alt="" class="wp-image-87977" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28.png 836w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-300x127.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-768x325.png 768w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-60x25.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-113x48.png 113w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-227x96.png 227w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.28-313x133.png 313w" sizes="auto, (max-width: 836px) 100vw, 836px" /></figure>



<p class="has-text-align-right">(1.29)</p>



<h2 class="wp-block-heading"><strong><u>CSTR Performance Equation</u></strong></h2>



<p><strong> </strong>The performance equation relates the reaction rate, volume, feed rate, and conversion of the species and we can rearrange the CSTR mole balance to get the performance equation and be able to work out the space-time or space velocity.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="246" height="158" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55.png" alt="" class="wp-image-87978" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55.png 246w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55-60x39.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55-75x48.png 75w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.08.55-149x96.png 149w" sizes="auto, (max-width: 246px) 100vw, 246px" /></figure>
</div>


<p class="has-text-align-right">(1.29)</p>



<p>Then we can use the space-time equation seen previously:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="578" height="262" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10.png" alt="" class="wp-image-87979" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10.png 578w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-300x136.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-60x27.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-106x48.png 106w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-212x96.png 212w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.09.10-313x142.png 313w" sizes="auto, (max-width: 578px) 100vw, 578px" /></figure>
</div>


<h2 class="wp-block-heading"><strong><u>PFR Performance Equation</u></strong></h2>



<p><strong> </strong>Assuming constant density,</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="922" height="354" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29.png" alt="" class="wp-image-87983" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29.png 922w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-300x115.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-768x295.png 768w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-60x23.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-125x48.png 125w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-250x96.png 250w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.29-313x120.png 313w" sizes="auto, (max-width: 922px) 100vw, 922px" /></figure>
</div>


<p>C<sub>AF </sub>– final concentration of species A</p>



<p>If the elementary reaction is given, we can easily form an expression for r<sub>A </sub>in terms of conversion and then integrate to find out the space-time.</p>



<p>To be able to solve the integral, Simpson’s rule will need to be used, and depending on your university lecturer you could be given the Simpson’s rule formula, but if not it isn’t too hard to learn and the best way to learn is to practice and try as many variations of questions at different levels of difficulty to get used to answering these equations which are usually heavily weighted in terms of marks.</p>



<p>The equation below is Simpsons 3<sup>rd</sup> rule this can usually be used most of the time unless stated otherwise.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="732" height="110" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38.png" alt="" class="wp-image-87984" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38.png 732w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-300x45.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-60x9.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-319x48.png 319w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-639x96.png 639w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.11.38-313x47.png 313w" sizes="auto, (max-width: 732px) 100vw, 732px" /></figure>
</div>


<p class="has-text-align-right">(1.35)</p>



<h2 class="wp-block-heading"><strong><u>Changing Density </u></strong></h2>



<p>When the number of moles of gas, temperature or pressure changes then the density will no longer be constant, and we can then use the ideal gas law and then using the initial conditions and the final conditions inside the <strong>batch</strong> reactor and rationing them out:</p>



<p>Ideal gas law: pV =nRT</p>



<p>p – Pressure</p>



<p>V – Volume</p>



<p>n- Moles</p>



<p>R – Universal gas constant</p>



<p>T – Temperature</p>



<p>Initial conditions of gas:</p>



<figure class="wp-block-image size-full"><img loading="lazy" decoding="async" width="308" height="206" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02.png" alt="" class="wp-image-87985" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02.png 308w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02-300x201.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02-60x40.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02-72x48.png 72w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.02-144x96.png 144w" sizes="auto, (max-width: 308px) 100vw, 308px" /></figure>



<p>Final conditions of gas: pV =nRT</p>



<p>This is simply the initial number of moles plus the change in the total number of moles due to the reaction taking place.</p>



<p>Now we will introduce epsilon, &nbsp;which is the change in the number of moles of the limiting reactant after the reaction has taken place, divided by the original number of moles.</p>



<figure class="wp-block-image size-full"><img loading="lazy" decoding="async" width="880" height="100" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35.png" alt="" class="wp-image-87986" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35.png 880w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-300x34.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-768x87.png 768w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-60x7.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-422x48.png 422w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-845x96.png 845w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.35-313x36.png 313w" sizes="auto, (max-width: 880px) 100vw, 880px" /></figure>



<p class="has-text-align-right">(1.39)</p>



<p>Then we can say, in a situation where species A is the limiting reagent</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="216" height="62" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.48.png" alt="" class="wp-image-87987" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.48.png 216w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.48-60x17.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.12.48-167x48.png 167w" sizes="auto, (max-width: 216px) 100vw, 216px" /></figure>
</div>


<p class="has-text-align-right">(1.40)</p>



<p>Remember, the total number of moles includes the leftover reactants that are in excess and any inert species that are present.</p>



<p>Using the change in moles formula, equation 1.37 into the volume equation 1.37:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="330" height="168" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07.png" alt="" class="wp-image-87989" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07.png 330w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-300x153.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-60x31.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-94x48.png 94w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-189x96.png 189w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.07-313x159.png 313w" sizes="auto, (max-width: 330px) 100vw, 330px" /></figure>
</div>


<p>For <strong>a flow reactor, </strong>the volume is replaced with the volume flow rate:</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="320" height="108" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23.png" alt="" class="wp-image-87990" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23.png 320w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-300x101.png 300w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-60x20.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-142x48.png 142w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-284x96.png 284w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-17-at-20.13.23-313x106.png 313w" sizes="auto, (max-width: 320px) 100vw, 320px" /></figure>
</div>


<p class="has-text-align-right">(1.41)</p>



<p>When the density is constant, we can assume that is equal to zero.</p>



<p><strong>Example – limiting reagent </strong></p>



<p><strong>&nbsp;</strong>Air is comprised of roughly 21% oxygen, and the input feed to a reactor is 100 moles and sulphur dioxide is added as well and the input mixture is 28% sulphur dioxide and the remainder is air, the desired product is sulphur trioxide, what is the limiting reagent? and why?</p>



<p class="has-text-align-center">2SO2 + O2 → 2SO3</p>


<input type='hidden' bg_collapse_expand='69af953a2edc83023331835' value='69af953a2edc83023331835'><input type='hidden' id='bg-show-more-text-69af953a2edc83023331835' value='Show Answer'><input type='hidden' id='bg-show-less-text-69af953a2edc83023331835' value='Hide Answer'><button id='bg-showmore-action-69af953a2edc83023331835' class='bg-showmore-plg-button bg-blue-button bg-eye '   style=" color:#ffffff;">Show Answer</button><div id='bg-showmore-hidden-69af953a2edc83023331835' >
<p style="text-align: left"><strong>Answer – limiting reagent</strong></p>
<p><strong> </strong>Air makes up = 100 – 28 = 72 moles</p>
<p>And as oxygen is 21%, the amount of oxygen is = 0.21 x 72 = 15.12 mol</p>
<p>This means that sulphur dioxide is the limiting reagent because the 28 moles of sulphur dioxide need only 15.12 moles of oxygen to react.</p>
</div>



<h2 class="wp-block-heading"><u>References</u></h2>



<p>The Essential Chemical Industry &#8211; online. (2013, March 18). <em>Chemical reactors</em>. Retrieved from The Essential Chemical Industry &#8211; online: https://www.essentialchemicalindustry.org/processes/chemical-reactors.html</p>



<p>Vapourtec. (2020). <em>Continuous Stirred Tank Reactor (CSTR)</em>. Retrieved from Vapourtec: https://www.vapourtec.com/flow-chemistry/continuous-stirred-tank-reactor-cstr/</p>



<p>Vapourtec. (2020). <em>Plug flow reactor</em>. Retrieved from Vapourtec: https://www.vapourtec.com/flow-chemistry/plug-flow-reactor/</p>



<p>Wikipedia. (2020). <em>Continuous stirred-tank reactor</em>. Retrieved from Wikipedia: https://en.wikipedia.org/wiki/Continuous_stirred-tank_reactor</p>



<p>Wikipedia. (2020). <em>Plug flow reactor model</em>. Retrieved from Wikipedia: https://en.wikipedia.org/wiki/Plug_flow_reactor_model</p>
<div class="saboxplugin-wrap" itemtype="http://schema.org/Person" itemscope itemprop="author"><div class="saboxplugin-tab"><div class="saboxplugin-gravatar"><img loading="lazy" decoding="async" src="https://engineeringness.com/wp-content/uploads/2025/04/1734789673907.jpeg" width="100"  height="100" alt="" itemprop="image"></div><div class="saboxplugin-authorname"><a href="https://engineeringness.com/author/dr-adam-zaidi/" class="vcard author" rel="author" data-wpel-link="internal"><span class="fn">Dr. Adam Zaidi</span></a></div><div class="saboxplugin-desc"><div itemprop="description"><p>Dr. Adam Zaidi, PhD, is a researcher at The University of Manchester (UK). His doctoral research focuses on reducing carbon dioxide emissions in hydrogen production processes. Adam&#8217;s expertise includes process scale-up and material development.’</p>
</div></div><div class="clearfix"></div></div></div><p>The post <a href="https://engineeringness.com/an-in-depth-breakdown-pfr-and-cstr-reactor-design/" data-wpel-link="internal">An In-Depth Breakdown | PFR and CSTR Reactor Design</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
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		<title>Batch And Levenspiel Plots For Parallel And Series Reactors</title>
		<link>https://engineeringness.com/batch-and-levenspiel-plots-for-parallel-and-series-reactors/</link>
					<comments>https://engineeringness.com/batch-and-levenspiel-plots-for-parallel-and-series-reactors/#respond</comments>
		
		<dc:creator><![CDATA[Dr. Adam Zaidi]]></dc:creator>
		<pubDate>Fri, 28 Aug 2020 17:17:57 +0000</pubDate>
				<category><![CDATA[Kinetics]]></category>
		<category><![CDATA[Batch Reactors]]></category>
		<category><![CDATA[CSTR]]></category>
		<category><![CDATA[PFR]]></category>
		<category><![CDATA[Parallel series]]></category>
		<category><![CDATA[Parallel reactors]]></category>
		<category><![CDATA[Levenspiel]]></category>
		<guid isPermaLink="false">http://52.205.3.27/?p=83185</guid>

					<description><![CDATA[<p>Batch and Levenspiel Plots A Batch reactor plot is a graphical representation of the volume of an isothermal system. General shape of a Batch Reactor (Advanced Energy Materials Processing Laboratory, 2020) Batch reactor plot (Advanced Energy Materials Processing Laboratory, 2020) A Levenspiel plot is a representation of the continuous flow reactor; CSTR and PFR design equations as a function of conversion and is used to determine the volume of the reactor. Shape of CSTR and PFR (Advanced Energy Materials Processing Laboratory, 2020) PFR and CSTR Levenspiel Plot Comparison The rate used for the CSTR is evaluated at the exit stream</p>
<p>The post <a href="https://engineeringness.com/batch-and-levenspiel-plots-for-parallel-and-series-reactors/" data-wpel-link="internal">Batch And Levenspiel Plots For Parallel And Series Reactors</a> appeared first on <a href="https://engineeringness.com" data-wpel-link="internal">Engineeringness</a>.</p>
]]></description>
										<content:encoded><![CDATA[
<h2 class="wp-block-heading"><u>Batch and Levenspiel Plots</u></h2>



<p>A Batch reactor plot is a graphical representation of the volume of an isothermal system.</p>


<div class="wp-block-image">
<figure class="aligncenter"><img loading="lazy" decoding="async" width="520" height="168" src="http://engineeringness.com/wp-content/uploads/2020/08/Picture1-e1711086309291.png" alt="" class="wp-image-83186" srcset="https://engineeringness.com/wp-content/uploads/2020/08/Picture1-e1711086309291.png 520w, https://engineeringness.com/wp-content/uploads/2020/08/Picture1-e1711086309291-300x97.png 300w, https://engineeringness.com/wp-content/uploads/2020/08/Picture1-e1711086309291-60x19.png 60w, https://engineeringness.com/wp-content/uploads/2020/08/Picture1-e1711086309291-149x48.png 149w, https://engineeringness.com/wp-content/uploads/2020/08/Picture1-e1711086309291-297x96.png 297w, https://engineeringness.com/wp-content/uploads/2020/08/Picture1-e1711086309291-313x101.png 313w" sizes="auto, (max-width: 520px) 100vw, 520px" /></figure>
</div>


<p class="has-text-align-center"><strong>General shape of a Batch Reactor (Advanced Energy Materials Processing Laboratory, 2020)</strong></p>


<div class="wp-block-image">
<figure class="aligncenter"><img loading="lazy" decoding="async" width="854" height="291" src="http://engineeringness.com/wp-content/uploads/2020/08/Screenshot-2020-08-25-at-17.54.23-e1711086290500.png" alt="" class="wp-image-83191" srcset="https://engineeringness.com/wp-content/uploads/2020/08/Screenshot-2020-08-25-at-17.54.23-e1711086290500.png 854w, https://engineeringness.com/wp-content/uploads/2020/08/Screenshot-2020-08-25-at-17.54.23-e1711086290500-300x102.png 300w, https://engineeringness.com/wp-content/uploads/2020/08/Screenshot-2020-08-25-at-17.54.23-e1711086290500-768x262.png 768w, https://engineeringness.com/wp-content/uploads/2020/08/Screenshot-2020-08-25-at-17.54.23-e1711086290500-60x20.png 60w, https://engineeringness.com/wp-content/uploads/2020/08/Screenshot-2020-08-25-at-17.54.23-e1711086290500-141x48.png 141w, https://engineeringness.com/wp-content/uploads/2020/08/Screenshot-2020-08-25-at-17.54.23-e1711086290500-282x96.png 282w, https://engineeringness.com/wp-content/uploads/2020/08/Screenshot-2020-08-25-at-17.54.23-e1711086290500-313x107.png 313w" sizes="auto, (max-width: 854px) 100vw, 854px" /></figure>
</div>


<p class="has-text-align-center"><strong>Batch reactor plot (Advanced Energy Materials Processing Laboratory, 2020)</strong></p>



<p>A Levenspiel plot is a representation of the continuous flow reactor; CSTR and PFR design equations as a function of conversion and is used to determine the volume of the reactor.</p>


<div class="wp-block-image">
<figure class="aligncenter"><img loading="lazy" decoding="async" width="535" height="504" src="http://engineeringness.com/wp-content/uploads/2020/08/picture-2.png" alt="" class="wp-image-83192" srcset="https://engineeringness.com/wp-content/uploads/2020/08/picture-2.png 535w, https://engineeringness.com/wp-content/uploads/2020/08/picture-2-300x283.png 300w" sizes="auto, (max-width: 535px) 100vw, 535px" /></figure>
</div>


<p class="has-text-align-center"><strong>Shape of CSTR and PFR (Advanced Energy Materials Processing Laboratory, 2020)</strong></p>



<h2 class="wp-block-heading"><strong><u>PFR and CSTR Levenspiel Plot Comparison</u></strong></h2>



<p>The rate used for the CSTR is evaluated at the exit stream conditions while for the PFR the rate used is integrated over a range of conditions and we can solve this using Simpsons composite rule,</p>


<div class="wp-block-image">
<figure class="aligncenter"><img loading="lazy" decoding="async" width="800" height="372" src="http://engineeringness.com/wp-content/uploads/2020/08/picture-3.png" alt="" class="wp-image-83194" srcset="https://engineeringness.com/wp-content/uploads/2020/08/picture-3.png 800w, https://engineeringness.com/wp-content/uploads/2020/08/picture-3-300x140.png 300w, https://engineeringness.com/wp-content/uploads/2020/08/picture-3-768x357.png 768w" sizes="auto, (max-width: 800px) 100vw, 800px" /></figure>
</div>


<p class="has-text-align-center"><strong>CSTR and PFR Levenspiel plot (Advanced Energy Materials Processing Laboratory, 2020)</strong></p>



<ul class="wp-block-list">
<li>PFR requires a smaller volume than the CSTR for a given conversion</li>



<li>When the reaction speed increases for a CSTR the Levenspiel plot will curve downwards as the conversion changes and will require a smaller CSTR volume.</li>
</ul>



<h2 class="wp-block-heading"><strong><u>Levenspiel Plot For Reactor In A Series Arrangement </u></strong></h2>



<p>PFR in series act as one large PFR and if the density is constant then the residence time is just the space time at the inlet conditions. For a CSTR multiple CSTRs in series require a smaller volume as a CSTR is evaluated at the output conditions and will make a series of CSTR’s smaller than one large CSTR, as when using multiple CSTRs the first tank operates at a lower conversion so the concentration of reactants will be higher so the rate will be greater and the volume required will be smaller.</p>



<p>CSTRs in series get close to the performance of PFR and the smaller the CSTRs the closer they get, but financial costs and available space and other factors make having lots of small CSTRs not practical when one PFR can be used.</p>


<div class="wp-block-image">
<figure class="aligncenter"><img loading="lazy" decoding="async" width="820" height="597" src="http://engineeringness.com/wp-content/uploads/2020/08/picture-4.png" alt="" class="wp-image-83197" srcset="https://engineeringness.com/wp-content/uploads/2020/08/picture-4.png 820w, https://engineeringness.com/wp-content/uploads/2020/08/picture-4-300x218.png 300w, https://engineeringness.com/wp-content/uploads/2020/08/picture-4-768x559.png 768w" sizes="auto, (max-width: 820px) 100vw, 820px" /></figure>
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<p class="has-text-align-center"><strong>CSTR Levenspiel plot in series (MIT, 2007)</strong></p>



<h2 class="wp-block-heading"><strong><u>Parallel Reactors</u></strong></h2>



<p>Parallel reactors for equal-sized flow reactors, the feed stream is split evenly between the reactors. Parallel reactor arrangement is used for CSTRs as the reactors will be operating at the lowest conversion will be better to operate in series. For PFRs this arrangement behaves as one large PFR and is a common arrangement as used in industry or in Labourites.</p>


<div class="wp-block-image">
<figure class="aligncenter"><img loading="lazy" decoding="async" width="664" height="304" src="http://engineeringness.com/wp-content/uploads/2020/08/picture-5.png" alt="" class="wp-image-83200" srcset="https://engineeringness.com/wp-content/uploads/2020/08/picture-5.png 664w, https://engineeringness.com/wp-content/uploads/2020/08/picture-5-300x137.png 300w" sizes="auto, (max-width: 664px) 100vw, 664px" /></figure>
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<p class="has-text-align-center"><strong>PFR in a parallel arrangement (Santofimio, 2020)</strong></p>



<h2 class="wp-block-heading"><strong><u>PFR With Recycle</u></strong></h2>



<p>Unreacted reactants can be recycled from the PFR exit stream, we define a recycle ratio, R when it is equal to zero (R = 0) then we have standard/normal plug flow and as R increases we develop mixed flow and the PFR starts to resemble the behaviour of a CSTR.</p>



<p class="has-text-align-center">R&nbsp;=&nbsp;Volume&nbsp;of&nbsp;fluid&nbsp;recycledVolume&nbsp;of&nbsp;fluid&nbsp;leaving&nbsp;PFR</p>



<p class="has-text-align-right">(1.11)</p>



<p>We will be adding two new terms, single-pass conversion X<sub>S</sub> and overall conversion X<sub>O</sub>, the equations are below and have used species ‘A’ to represent the species used.</p>


<div class="wp-block-image">
<figure class="aligncenter size-full"><img loading="lazy" decoding="async" width="294" height="168" src="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-18-at-01.22.18.png" alt="" class="wp-image-87999" srcset="https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-18-at-01.22.18.png 294w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-18-at-01.22.18-60x34.png 60w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-18-at-01.22.18-84x48.png 84w, https://engineeringness.com/wp-content/uploads/2024/04/Screenshot-2024-04-18-at-01.22.18-168x96.png 168w" sizes="auto, (max-width: 294px) 100vw, 294px" /></figure>
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<p>Single-pass conversion shows the fraction that is converted when it goes through the PFR once and overall conversion is the fraction converted in the final stream from the total inlet flow.</p>


<div class="wp-block-image">
<figure class="aligncenter"><img loading="lazy" decoding="async" width="922" height="277" src="http://engineeringness.com/wp-content/uploads/2020/08/PICTURE-6.png" alt="" class="wp-image-83201" srcset="https://engineeringness.com/wp-content/uploads/2020/08/PICTURE-6.png 922w, https://engineeringness.com/wp-content/uploads/2020/08/PICTURE-6-300x90.png 300w, https://engineeringness.com/wp-content/uploads/2020/08/PICTURE-6-768x231.png 768w" sizes="auto, (max-width: 922px) 100vw, 922px" /></figure>
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<p class="has-text-align-center"><strong>PFR with recycle diagram (Cheggstudy, 2020)</strong></p>



<p>PFR with recycle is a difficult concept to get your head around and has a lot of keywords, that can trip you up if you don’t pay attention them, the best way is to do an example whilst looking at the answers and see what steps to do to solve this type of question in an exam, if you can do this example exam question without looking at the answers it will be extremely impressive!</p>



<p><strong>Example – PFR with recycle (typical exam question)</strong></p>



<p>In a PFR with recycle a reaction that is elementary and, in the liquid phase takes places, with an R = 1 and a conversion of 2/3, what is the conversion if there is no recycle stream?</p>


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<p><strong>Answer – PFR with recycle</strong></p>
<p><u>First: do PFR <strong>with</strong> recycle stream</u></p>
<p>As liquid phase reaction only, the density is constant so the volumetric flow rate is constant, we will use the PFR mole balance but will use a slightly different version, this will help as there are different conversions and can be tricky to do.</p>
<p>Mole Balance PFR:</p>
<p style="text-align: center">∆FA = rA∆V</p>
<p>Rate Equation:</p>
<p style="text-align: center">-rA = kCA2</p>
<p>From Stoichiometry:</p>
<p style="text-align: center">FA = vCA</p>
<p>Draw the diagram as seen above with the information we already have; this will help you visualise the problem:</p>
<p><img loading="lazy" decoding="async" class="aligncenter wp-image-83203 size-full" src="http://engineeringness.com/wp-content/uploads/2020/08/PICTURE-8-1.png" alt="" width="939" height="331" srcset="https://engineeringness.com/wp-content/uploads/2020/08/PICTURE-8-1.png 939w, https://engineeringness.com/wp-content/uploads/2020/08/PICTURE-8-1-300x106.png 300w, https://engineeringness.com/wp-content/uploads/2020/08/PICTURE-8-1-768x271.png 768w" sizes="auto, (max-width: 939px) 100vw, 939px" /></p>
<p>The volumetric flow rate (v) is initially:</p>
<p>v0</p>
<p>and as the recycle ratio is one the volumetric flow rate in the recycle is same as feed stream, thus the stream going into the reactor after the recycle would be:</p>
<p style="text-align: center">v0 + v0 = 2v0</p>
<p>The final concentration is:</p>
<p style="text-align: center">CAf = CA03</p>
<p>as the conversion is 2/3, this is from the overall conversion.</p>
<p>The concentration in the feed stream is:</p>
<p style="text-align: center">CA1 = (CA0 + CAf) × 12 = 2CA03</p>
<p>this is because the volumetric flow rates are equal in the recycle stream and the feed stream. We multiply by a ½ as the recycle stream and feed are equal so assume perfect mixing.</p>
<p>Now take the PFR mole balance and the stoichiometric relationship to get:</p>
<p style="text-align: center">v∆CA = rA∆V</p>
<p>And as volumetric flow rate into the reactor is:</p>
<p style="text-align: center">v = 2v0</p>
<p>we therefore get:</p>
<p style="text-align: center">2v0∆CA = rA∆V</p>
<p>This can be rearranged to:</p>
<p style="text-align: center">∆CArA=∆V2v0</p>
<p>Then substitute in the rate law:</p>
<p style="text-align: center">∆CA-KCA2=∆V2v0</p>
<p>Now integrate to get:</p>
<p style="text-align: center">∫CA1CAf1KCA = V2v0</p>
<p style="text-align: center">1KCAf &#8211; 1KCA1 = V2v0</p>
<p>We already know the values of the concentrations, so the left-hand side of the equation becomes:</p>
<p style="text-align: center">1KCAf3-1K2CA13 = 32KCA0</p>
<p style="text-align: center">32KCA0= V2v0or KVCA0v0 = 3</p>
<p>This above relationship will be true whether the recycle stream is on or not!</p>
<p><u>Second: do PFR <strong>without</strong> recycle stream</u>:</p>
<p>Mole balance PFR:</p>
<p style="text-align: center">∆FA = rA∆V</p>
<p>As no recycle the volumetric flow rate entering the reactor is:</p>
<p style="text-align: center">v0</p>
<p>Thus, combining stoichiometry and mole balance:</p>
<p style="text-align: center">v0∆CA=rA∆V</p>
<p>Now substitute in rate equation and integrate:</p>
<p style="text-align: center">∫CA1C*Af1KCA = Vv0</p>
<p>We have put an * on C<sub>Af</sub> as this value will be different when the recycle stream is on.</p>
<p style="text-align: center">1C*Af-1CA1 =KVv0</p>
<p style="text-align: center">CA0C*Af-1 = CA0KVv0 = 3</p>
<p>Therefore:</p>
<p style="text-align: center">CA0C*Af = 4</p>
<p>So, the <strong>exit</strong> concentration (C*<sub>Af</sub> ) without recycle is ¼ of the feed concentration.</p>
<p>Conversion without Recycle:</p>
<p style="text-align: center">X0 = 1-14 = 34</p>
<p>Conversion with Recycle: 2/3</p>
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<p></p>



<h2 class="wp-block-heading"><u>References</u></h2>



<p>Advanced Energy Materilas Processing Laboratory. (2020). <em>CHE 309: Chemical Reaction Engineering.</em> Retrieved from Advanced Energy Materilas Processing Laboratory: http://aempl.kist.re.kr/wp-content/files/Lecture-5_Ch2.pdf</p>



<p>Cheggstudy. (2020). <em>Question: Problem 3: Recycle Reactor.</em> Retrieved from Cheggstudy: https://www.chegg.com/homework-help/questions-and-answers/problem-3-recycle-reactor-farmer-michael-process-setting-recycle-reactor-farm-reaction-tak-q26913611</p>



<p>MIT. (2007). <em>PFR vs. CSTR: Size and Selectivity</em>. Retrieved from MIT: https://ocw.mit.edu/courses/chemical-engineering/10-37-chemical-and-biological-reaction-engineering-spring-2007/lecture-notes/lec09_03072007_w.pdf</p>



<p>Santofimio, D. S. (2020). <em>Parallel Reactors.docx.</em> Retrieved from Scribd: https://www.scribd.com/document/242835751/Parallel-Reactors-docx</p>
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